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pentagon [3]
3 years ago
10

Which expression is modeled by this se of arrows in the number line

Mathematics
1 answer:
Bond [772]3 years ago
7 0

Answer:

b

Step-by-step explanation:

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Help!! i need to get this done soon
Aliun [14]

Answer: i think the answer is (A)

Step-by-step explanation:

I recalculated and the other person was correct, sorry for the mix up

7 0
3 years ago
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At the newest animated movie, for every 9 children, there are 4 adults. There are a total of 39 children and adults at the movie
WARRIOR [948]
For every 9 children, there are 4 adults.
If there are 39 children and adults, we can work backwards to find the answer.

Lets start by multiplying 9. Lets do 3. 9 x 3 = 27.
Ok, now we have an estimate of 27 Children, now all we have to do is multiply the number of adults by 3.
Now we can multiply 4 x 3. 4 x 3 = 12. Now we have the number of children and adults.
Now lets add these together. 12 + 27 = 39! Perfect! Now we know that there are 27 children, and 12 adults.

Hope this helps!!
8 0
3 years ago
Aria paid $75,000 for her house. Its property value increased by 2.2% per year. When Aria sold her house after eleven years, how
astra-53 [7]

Answer:

When Aria sold her house after eleven years it worth was <u>$95,300</u>.

Step-by-step explanation:

Given:

Aria paid $75,000 for her house. Its property value increased by 2.2% per year.

Now, to find the worth of Aria house when sold after eleven years.

Let the amount of house after eleven years be x.

Amount Aria paid for her house (A) = $75,000.

Rate of property increased per year (r) = 2.2%.

Time (t) = 11 years.

Now, to get the amount of house after eleven years we put formula:

x=A\times (1+\frac{r}{100})^{11}

x=75000\times (1+\frac{2.2}{100})^{11}

x=75000\times (1+0.022)^{11}

x=75000\times (1.022)^{11}

x=75000\times 1.2704

x=95280.

<em>The amount of house after eleven years to the nearest hundred dollars is $95,300.</em>

Therefore, when Aria sold her house after eleven years it worth was $95,300.

3 0
3 years ago
7/3 into a mix number
goldenfox [79]

Answer: 2 1/3

Step-by-step explanation:

3 0
3 years ago
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Which expression is equivalent to RootIndex 3 StartRoot 32 x Superscript 8 Baseline y Superscript 10 Baseline EndRoot?
evablogger [386]

Answer:

The equivalent expression to the given expression is \sqrt[3]{32x^8y^{10}}=2x^2y^3\sqrt[3]{4x^2y}

Step-by-step explanation:

The given expression is \sqrt[3]{32x^8y^{10}}

To find the equivalent expression:

\sqrt[3]{32x^8y^{10}}=(32x^8y^{10})^{\frac{1}{3}}

We may write the above expression as below:

=(32^{\frac{1}{3}})((x^8)^{\frac{1}{3}})((y^{10})^{\frac{1}{3}})

=(2)((4)^{\frac{1}{3}})(x^6)\times (x^2)(x^{\frac{2}{3}})(y^3)(y^{\frac{1}{3}}) (using square root properties)

=(2\sqrt[3]{4})(x^2\sqrt[3]{x^2})(y^3\sqrt[3]{y}) (combining the like terms and doing multiplication )

=2x^2y^3\sqrt[3]{4x^2y}

Therefore \sqrt[3]{32x^8y^{10}}=2x^2y^3\sqrt[3]{4x^2y}

Therefore the equivalent expression to the given expression is \sqrt[3]{32x^8y^{10}}=2x^2y^3\sqrt[3]{4x^2y}

5 0
3 years ago
Read 2 more answers
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