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tester [92]
3 years ago
10

Y=x^2+2;D:-1, 0, 1, 2, 3

Mathematics
1 answer:
IrinaK [193]3 years ago
8 0

For the various values of X the values of Y are given as follows

X=-1; Y=3

X=0; Y=2

X=1; Y=3

X=2; Y=6

X=3; Y=11

Step-by-step explanation:

Step 1:

Let us consider the given expression as

Y= X^{2} + 2

Step 2:

Let us discuss the value of Y for the various values of X

If X = -1, Y = (-1)² + 2 = 3

If X = 0, Y = (0)² + 2 = 2

If X = 1, Y = (1)² + 2 = 3

If X = 2, Y = (2)² + 2 = 6

If X = 3, Y = (3)² + 2 = 11

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Marina sells candles that are in the shape of cones. she makes a yellow candle that has a diameter of 4 inches and a height of 1
Katena32 [7]

The correct statements are:

  • the volume of the yellow candle is about 46.05 inches cubed.
  • the radius of the yellow candle is 2 in
  • he base area of the yellow candle is about 6.28 inches squared.
  • the price of one yellow candle is about $16.12.

<h3>What are the correct statements?</h3>

Volume of a cone = 1/3(πr²h)

  • π = 3.14
  • r = radius = diameter / 2 = 4/2 = 2 inches
  • h = height

Volume of a cone = 1/3 x 2² x 11 x 3.14 = 46.05 inches cubed.

Base area = πr²

3.14 x 4 =  12.56 inches squared.

Price of one yellow candle = volume x price per cubic unit

46.05 x  $0.35 = $16.12

To learn more about the volume of a cone, please check: brainly.com/question/13705125

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3 0
2 years ago
Plz help don’t understand this question and I got it wrong an i have to redo it
Paladinen [302]

Answer:

its B

Step-by-step explanation:

7 0
2 years ago
Elevations above sea level are given as positive values, while elevations below sea level are given as negative values. Tina is
UkoKoshka [18]

|-80|=80

|x| -≥ this symbol is named as mod

we use this to find the absolute value...

it can be explained easily as meaning like rounding off

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negative number can never be the answer of absolute value

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2 years ago
Evaluate the difference quotient for the given function. Simplify your answer.
nasty-shy [4]

I suppose you mean

f(x) = \dfrac{x+5}{x+1}

Then

f(3) = \dfrac{3+5}{3+1} = \dfrac84 = 2

and the difference quotient is

\dfrac{f(x)-f(3)}{x-3} = \dfrac{\frac{x+5}{x+1}-2}{x-3} \\\\ \dfrac{f(x)-f(3)}{x-3} = \dfrac{\frac{x+5-2(x+1)}{x+1}}{x-3} \\\\ \dfrac{f(x)-f(3)}{x-3} = \dfrac{-x+3}{(x+1)(x-3)} \\\\ \dfrac{f(x)-f(3)}{x-3} = \boxed{-\dfrac{x-3}{(x+1)(x-3)}}

If it's the case that <em>x</em> ≠ 3, then (<em>x</em> - 3)/(<em>x</em> - 3) reduces to 1, and you would be left with

\dfrac{f(x)-f(3)}{x-3}\bigg|_{x\neq3} = -\dfrac1{x+1}

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2 years ago
Find the midpoint of A and B where A has coordinates (2, 4)<br> and B has coordinates (-3,-9).
Pavel [41]

Answer:

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y= -2.5

6 0
3 years ago
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