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skad [1K]
3 years ago
7

Perimeter help please quick !

Mathematics
1 answer:
Musya8 [376]3 years ago
4 0

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{x = 4.4}}}}}

Step-by-step explanation:

Given,

Length of the rectangle ( l ) = 3x + 5

Breadth of the rectangle ( b ) = 2x - 1

Perimeter of the rectangle ( P ) = 52

<u>Finding</u><u> </u><u>the</u><u> </u><u>value</u><u> </u><u>of</u><u> </u><u>x</u>

\boxed{ \sf{perimeter \: of \: rectangle = 2(l + b)}}

⇒\sf{52 = 2(3x + 5 + 2x - 1)}

⇒\sf{52 = 2(5x + 4)}

⇒\sf{52 = 10x + 8}

⇒\sf{10x + 8 = 52}

⇒\sf{10x = 52 - 8}

⇒\sf{10x = 44}

⇒\sf{ \frac{10x}{10}  =  \frac{44}{10} }

⇒\sf{x = 4.4 \: }

Hope I helped!

Best regards!! :D

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The isosceles triangle theorem states that if two sides of a triangle are congruent then the angles opposite those sides are congruent. The correct answer is option c.

<h3>What is the isosceles triangle?</h3>

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7 0
2 years ago
2/4 is what pieces of a whole
rewona [7]
2/4 is half of a whole
8 0
4 years ago
Read 2 more answers
Despeja g.<br> -3+5+6g=11-3g
Len [333]

Answer: The value of g is 1

Step-by-step explanation:

To solve for g in the algebraic expression below: collect like terms

-3+5+6g=11-3g

2 + 6g = 11 - 3g

Let the whole algebraic expression equal zero by moving 11 -3g to left hand side while the minus sign becomes plus sign '+' since it crossed the equality sign '=')

Thus, 2 + 6g - 11 + 3g = 0

collect like terms again

2 - 11 + 6g + 3g = 0

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-9 = -9g

Divide both sides by -9

-9/-9 = -9g/-9

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Thus, the value of g is 1

5 0
3 years ago
Please help asap, will give brainliest. There are 2 answers, it’s multiple choice
umka2103 [35]
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6 0
3 years ago
What is the correct first step to solve this system of equations by elimination?
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\bold{\huge{\pink{\underline{ Solution }}}}

\bold{\underline{ Given }}

  • <u>We </u><u>have </u><u>given </u><u>two </u><u>linear </u><u>equations </u><u>that</u><u> </u><u>is </u><u>2x </u><u>-</u><u> </u><u>3y </u><u>=</u><u> </u><u>-</u><u>6</u><u> </u><u>and </u><u>x</u><u> </u><u>+</u><u> </u><u>3y </u><u>=</u><u> </u><u>1</u><u>2</u><u> </u><u>.</u>

\bold{\underline{ To \: Find }}

  • <u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>value </u><u>of </u><u>x </u><u>and </u><u>y </u><u>by </u><u>elimination </u><u>method</u><u>. </u>

\bold{\underline{ Let's \: Begin }}

\sf{ 2x - 3y = -6 ...eq(1)}

\sf{ x +  3y = 12 ...eq(2)}

<u>Multiply </u><u>eq(</u><u> </u><u>2</u><u> </u><u>)</u><u> </u><u>by </u><u>2</u><u> </u><u>:</u><u>-</u>

\sf{ 2( x + 3y = 12 )}

\sf{ 2x + 6y = 24 }

<u>Subtract </u><u>eq(</u><u>1</u><u>)</u><u> </u><u>from </u><u>eq(</u><u>2</u><u>)</u><u> </u><u>:</u><u>-</u>

\sf{ 2x + 6y -( 2x - 3y) = 24 -(-6)}

\sf{ 2x + 6y - 2x + 3y = 24 + 6 }

\sf{   9y = 30 }

\sf{   y = 30/9}

\sf{\red{ y = 10/3}}

<u>Now</u><u>, </u><u> </u><u>Subsitute</u><u> </u><u>the </u><u>value </u><u>of </u><u>y </u><u>in </u><u>eq(</u><u> </u><u>1</u><u> </u><u>)</u><u>:</u><u>-</u>

\sf{ 2x - 3(10/3) = -6 }

\sf{ 2x - 10 = -6 }

\sf{ 2x  = -6 + 10}

\sf{ x  = 4/2}

\sf{\red{ x  = 2}}

Hence, The value of x and y is 2 and 10/3

6 0
3 years ago
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