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skad [1K]
3 years ago
7

Perimeter help please quick !

Mathematics
1 answer:
Musya8 [376]3 years ago
4 0

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{x = 4.4}}}}}

Step-by-step explanation:

Given,

Length of the rectangle ( l ) = 3x + 5

Breadth of the rectangle ( b ) = 2x - 1

Perimeter of the rectangle ( P ) = 52

<u>Finding</u><u> </u><u>the</u><u> </u><u>value</u><u> </u><u>of</u><u> </u><u>x</u>

\boxed{ \sf{perimeter \: of \: rectangle = 2(l + b)}}

⇒\sf{52 = 2(3x + 5 + 2x - 1)}

⇒\sf{52 = 2(5x + 4)}

⇒\sf{52 = 10x + 8}

⇒\sf{10x + 8 = 52}

⇒\sf{10x = 52 - 8}

⇒\sf{10x = 44}

⇒\sf{ \frac{10x}{10}  =  \frac{44}{10} }

⇒\sf{x = 4.4 \: }

Hope I helped!

Best regards!! :D

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It takes 30 minutes or less to walk from home to school and back home again when walking at 30m/min to school and walking at 45
erik [133]

Answer:

540m

Step-by-step explanation:

From the question,we are told

It takes 30 minutes or less to walk from home to school and back home again

Time walking to school = 30 or less minutes

Time walking from school = 30 less minutes

Speed walking to school = 30m/min

Speed walking from school = 45m/min

The question asked us to find the Distance between home and school

The formula for Distance covered = Speed × Time

Total distance = Total Speed(m/min) × Total time(minutes)

Let the distance between home and school be represented by x

Time to walk from the house to school = x/ 45m/min + x/ 30m/min

= 30 × x + 45 × x/1350

=( 75x / 1350)

Time to walk from school or to school = 30 minutes of less

= 75x/1350 = 30

75x = 1350 × 30

x = 1350 × 30/75

x = 540m

Therefore, distance between home and school = 540m

4 0
3 years ago
Find the volume of a cone with a height of 6 in and a base radius of 4 in
Neko [114]

Answer:

The answer is

<h2>100.5 in³</h2>

Step-by-step explanation:

The volume of a cone is given by

V  =  \frac{1}{3} \pi {r}^{2} h

where

r is the radius

h is the height of the cone

From the question

h = 6 in

r = 4 in

The volume of the cone is

V  =  \frac{1}{3}  \times  {4}^{2}  \times 6\pi \\  =  \frac{1}{3}  \times 16 \times 6\pi \\  =  \frac{1}{3}  \times 96\pi \\  = 32\pi \\  = 100.530964

We have the final answer as

100.5 in³

Hope this helps you

5 0
3 years ago
Read 2 more answers
answer for louis wants to carpet the rectangular floor of his basement. the basement has an area of 864 square feet. the width o
AnnZ [28]
Area=legnth times width
width=2/3 legnth
w=2/3l
a=lw
subsitute
a=l(2/3l)
a=864
864=2/3l^2
multiply both sides by 3/2 to clear fraction
2592/2=l^2
1296=l^2
square root both sides
36=legnth

width=2/3 legnth
width=2/3 times 36
width=72/3=24

legnth =36 feet
width=24 feet
6 0
3 years ago
A sheet of paper 90 cm-by-66 cm is made into an open box (i.e. there's no top), by cutting x-cm squares out of each corner and f
NNADVOKAT [17]

Answer:

26 - \sqrt{181} cm

Step-by-step explanation:

The volume of the box is:

V = height * length * width

V = x*(66 - 2*x)*(90 - 2*x)

V = (66*x - 2*x^2)*(90 - 2*x)

V = 5940*x - 132*x^2 - 180*x^2 + 4*x^3

V = 4*x^3 - 312*x^2 + 5940*x

where x is the length of the sides of the squares,  in cm.

The mathematical problem is :

Maximize: V = 4*x^3 - 312*x^2 + 5940*x

subject to:

x > 0

2*x < 66 <=> x < 33

In the maximum, the first derivative of V, dV/dx, is equal to zero

dV/dx = 12*x^2 - 624*x + 5940

From quadratic formula

x = \frac{-b \pm \sqrt{b^2 - 4(a)(c)}}{2(a)}

x = \frac{624 \pm \sqrt{(-624)^2 - 4(12)(5940)}}{2(12)}

x = \frac{624 \pm \sqrt{104256}}{24}

x = \frac{624 \pm \sqrt{2^6*3^2*181}}{24}

x = \frac{624 \pm 8*3*\sqrt{181}}{24}

x_1 = \frac{624 + 24*\sqrt{181}}{24}

x_1 = 26 + \sqrt{181}

x_2 = \frac{624 - 24*\sqrt{181}}{24}

x_2 = 26 - \sqrt{181}

But x_1 > 33, then is not the correct answer.

5 0
3 years ago
A figure composed of two quadrilaterals is shown.
Tems11 [23]

Answer:

D a reflection over a line through point P followed by a dilation centered at point P

6 0
3 years ago
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