Question

If the first and third of three consecutive even integers are added, the result is 22 less than three times the second integer. Find the integers

Answer 1

Three consecutive even integers are 20, 22 and 24

Explanation

Suppose, the three consecutive even integers are  $n, n+2$ and $n+4$

Given that, sum of first and third integers is 22 less than 3 times the second integer. So, the equation will be....

$n+(n+4)= 3(n+2)-22\\ \\ 2n+4=3n+6-22\\ \\ 2n-3n=6-22-4\\ \\ -n=-20 \\ \\ n=20$

So, the first integer is 20, the second integer is (20+2)= 22 and the third integer is (20+4)= 24