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2 years ago

The Radius of the inner circle is 2 cm and the radius of the outer circle is 6 cm

Mathematics

1 answer:

NeX [460]2 years ago

3 0

Answer:

31pi

Step-by-step explanation:

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I don't know what to do

Zarrin [17]

Check the picture below

use the far-arc near-arc equation

bear in mind, your far-arc and near-arc are both in y-terms, so, the angle will be in y-terms as well

3 0

2 years ago

Jace gathered the data in the table. He found the approximate line of best fit to be y = –0.7x + 2.36.

MaRussiya [10]

The residual value is -1.14.
Plug 5 into x
y=-0.7(5)+2.36
=-1.14

3 0

3 years ago

I need help on these two! Please and thank you! (:

ZanzabumX [31]

Answer:

Answers and methord in the pic

5 0

2 years ago

Read 2 more answers

Find the area of a rectangle that has the length of 2x-3 and the width of x .Someone painted an interior area of the rectangle a

Svet_ta [14]

Answer:

The area that was not painted is $(2x^{2}-6x+6)\ units^{2}$

Step-by-step explanation:

step 1

Find the area of the rectangle

we know that

The area of a rectangle is equal to

$A=LW$

In this problem we have

$L=2x-3$

$W=x$

substitute

$A=(2x-3)x\\A=(2x^{2}-3x)\ units^{2}$

step 2

Find the area that was painted

$A=(3)(x-2)\\A=(3x-6)\ units^{2}$

step 3

Find the area that was not painted

Subtract the area that was painted from the total area of rectangle

$A=(2x^{2}-3x)-(3x-6)=(2x^{2}-6x+6)\ units^{2}$

8 0

3 years ago

For questions 3 – 5, an airplane is heading south at an airspeed of 540 km/hr, but there is a wind blowing from the northeast at

GuDViN [60]

First, let's calculate the horizontal and vertical components of the wind speed (W) and the airplane speed (A), knowing that south is a bearing of 270° and northeast is a bearing of 45°:

$\begin{gathered} W_x=W\cos45°\\ \\ W_x=50\cdot0.707\\ \\ W_x=35.35\\ \\ \\ \\ W_y=W\sin45°\\ \\ W_y=50\cdot0.707\\ \\ W_y=35.35 \end{gathered}$ $\begin{gathered} A_x=A\cos270°\\ \\ A_x=540\cdot0\\ \\ A_x=0\\ \\ \\ \\ A_y=A\sin270°\\ \\ A_y=540\cdot(-1)\\ \\ A_y=-540 \end{gathered}$

Now, let's add the components of the same direction:

$\begin{gathered} V_x=W_x+A_x=35.35+0=35.35\\ \\ V_y=W_y+A_y=35.35-540=-504.65 \end{gathered}$

To find the resultant bearing (theta), we can use the formula below:

$\begin{gathered} \theta=\tan^{-1}(\frac{V_y}{V_x})\\ \\ \theta=\tan^{-1}(\frac{-504.65}{35.35})\\ \\ \theta=-86° \end{gathered}$

The angle -86° is equivalent to -86 + 360 = 274°.

Therefore the correct option is b.

8 0

1 year ago