Answer:
.
See the diagram attached below.
Let the chords be AB and AC with common point A.
AD is the diameter. Join B with D and C with D to form two triangles.
We need to prove that AB=AC.
\begin{gathered}In\ \triangle ABD\ and \triangle ACD;\\Given\ that\ \angle BAD=\angle CAD----(condition\ 1)\\since\ AD\ is\ diameter, \angle ABD=\angle ACD = 90^0\\So\ \angle ADB=\angle ADC--------(condition\ 2)\\AD=AD\ (common\ side)-----(condition\ 3)\\ \\So\ the\ triangles\ are\ congruent\ by\ ASA\ rule.\\Hence\ AB=AC.\end{gathered}
In △ABD and△ACD;
Given that ∠BAD=∠CAD−−−−(condition 1)
since AD is diameter,∠ABD=∠ACD=90
0
So ∠ADB=∠ADC−−−−−−−−(condition 2)
AD=AD (common side)−−−−−(condition 3)
So the triangles are congruent by ASA rule.
Hence AB=AC.
Angle 2 = 22 degrees (that line is dividing that angle into 1 & 2 equivalently)
Angle 3 = 90 degrees.
We assume that the function is as follows:
Then, we have that:
Thus, if we have that:
Therefore, the value for the function is f^-1(2) = -1/2 or
Hey! I know this is a bit late, but I realized I had the same question! Here is the answer to the question ;3Hope I helped! :D
Coin 1:The top box on the coin 1 section is QThe bottom box on the coin 1 section isNCoin 2:The first box on coin 2 is NThe second box is QThe third is QThe final box is N !Good luck~!
