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EastWind [94]
3 years ago
11

Respuesta para 8×-2=-9+7×

Mathematics
1 answer:
den301095 [7]3 years ago
8 0
The answer is x=-7
8x-7x-2=-9
8x-7x=-9+2
-7
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How do you do (a) and (b)?
bulgar [2K]

Answer:

See solution below

Step-by-step explanation:

(a) If n=0 or 1, the equation

(1)  y' = a(t)y + f(t)y^n

would be a simple linear differential equation. So, we can assume that n is different  to 0 or 1.

Let's use the following substitution:

(2) z=y^{n-1}

Taking the derivative implicitly and using the chain rule:

(3) z'=(1-n)y^{-n}y'

Multiplying equation (1) on both sides by

(1-n)y^{-n}

we obtain the equation

(1-n)y^{-n}y' = (1-n)y^{-n}a(t)y+(1-n)y^{-n}f(t)y^n

reordering:

(1-n)y^{-n}y' = (1-n)y^{-n}ya(t)+(1-n)y^{-n}y^nf(t)

(1-n)y^{-n}y' = (1-n)y^{1-n}a(t)+(1-n)y^{0}f(t)

(1-n)y^{-n}y' = (1-n)y^{1-n}a(t)+(1-n)f(t)

Now, using (2) and (3) we get:

z'= (1-n)za(t)+(1-n)f(t)

which is an ordinary linear differential equation with unknown function z(t).

(b)

The equation we want to solve is

(4)   xy'+ y = x^4 y^3  

Here, our independent variable is x (instead of t)

Assuming x different to 0, we divide both sides by x to obtain:

y'+\frac{1}{x}y = x^3 y^3

y' = -\frac{1}{x}y+x^3 y^3

Which is an equation of the form (1) with

a(x)=-\frac{1}{x}

f(x)=x^3

n=3

So, if we substitute

z=y^{-2}

we transform equation (4) in the lineal equation

(5) z'=\frac{2}{x}z-2x^3

and this is an ordinary lineal differential equation of first order whose

integrating factor is

e^{\int (-\frac{2}{x})dx}

but

e^{\int (-\frac{2}{x})dx}=e^{-2\int \frac{dx}{x}}=e^{-2ln(x)}=e^{ln(x^{-2})}=x^{-2}=\frac{1}{x^2}

Similarly,

e^{\int (\frac{2}{x})dx}=x^2

and the general solution of (5) is then

z(x)=x^2\int (\frac{-2x^3}{x^2})dx+Cx^2=-2x^2\int xdx+Cx^2=\\\ -2x^2\frac{x^2}{2}+Cx^2=-x^4+Cx^2

where C is any real constant

Reversing the substitution  

z=y^{-2}

we obtain the general solution of (4)

y=\sqrt{\frac{1}{z}}=\sqrt{\frac{1}{-x^4+Cx^2}}

Attached there is a sketch of several particular solutions corresponding to C=1,4,6

It is worth noticing that the solutions are not defined on x=0 and for C<0

4 0
3 years ago
6) HELP plz ASAP the last one plz help
eduard

Answer:

12

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Please help :( <br><br> Find the volume of the composite figure shown.
Allushta [10]

Answer:

Ello, estoy aquí para ayudar, pero hablo español, con suerte, entenderás que lo estoy intentando.

56738w7421098548091672949123749279102!

Step-by-step explanation:

8 0
3 years ago
Jim's work evaluating 2 (three-fifths) cubed is shown below. 2 (three-fifths) cubed = 2 (StartFraction 3 cubed Over 5 EndFractio
sammy [17]

Answer:

Jim's error is " He did not multiply Three-fifths by 2 before applying the power "

Step-by-step explanation:

Jim's evaluating expression is 2(\frac{3}{5})^3

To verify Jim's error :

Jim's steps are

2(\frac{3}{5})^3

=2(\frac{3^3}{5})

=2(\frac{3\times 3\times 3}{5})

=2(\frac{27}{5})

=\frac{54}{5}

Therefore 2(\frac{3}{5})^3=\frac{54}{5}

Jim's error is " He did not multiply Three-fifths by 2 before applying the power "

That is the corrected steps are

2(\frac{3}{5})^3

=2(\frac{3^3}{5^3})  ( using the property (\frac{a}{b})^m=\frac{a^m}{b^m} )

=2(\frac{3\times 3\times 3}{5\times 5\times 5})

=2(\frac{27}{125})

=\frac{54}{125}

2(\frac{3}{5})^3=\frac{54}{125}

6 0
3 years ago
Read 2 more answers
BRAINLIESTT ASAP! PLEASE HELP ME :)
Mamont248 [21]

Denali- 6.7x70= 469

The building should be strong enough to withstand an earthquake of that magnitude.

Rat Island- 7.8x30=234

The building should be string enough to withstand an earthquake of that magnitude.

Hope this helps! ;)

8 0
4 years ago
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