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notsponge [240]
2 years ago
8

Six more than 1/5 a number is 12. What is the number

Mathematics
1 answer:
suter [353]2 years ago
8 0

Answer:

Step-by-step explanation:

let x be the number

6+1/5x=12

1/5x=12-6

1/5x=6

x=5*6

x=30

check: 6+(1/5*30)=6+6=12

You might be interested in
(3 + 8i) + (7 -- 2i) - (6 - 5i)<br> AO 4+1<br> B.O4 + 117<br> c. 16 +1<br> D.O4 + 1143
Lubov Fominskaja [6]

Answer: (3 + 8i) + (7 -- 2i) - (6 - 5i) = 4 + 15i

_____________________________________________

Simplify the expression.

4 + 15i

_____________________________________________

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You are worth everything and more! So stay strong, hold on, and live long!  

Most people don't hear this often. Your all loved, no matter what it feels like. So please, stay strong. If not for yourself then for me and everyone else who cares for you...

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3 0
2 years ago
There are 195 adults and 320 children at a zoo. The zoo makes a total of $6,515 from the entrance fees, and the cost of an adult
Ostrovityanka [42]

Answer:

a+c=27

195a+320c=6515

Step-by-step explanation:

adult (a): 195

children (c): 320

total $: $6515

child $: 27

a+c=27 --> c=-a+27

195a+320c=6515

sub the first equation into the 2nd equation to get a=17

sub a=17 into c=-a+27 to get c=10

so, an adult ticket is $17 and a child ticket is $10.

6 0
2 years ago
A dataset lists full IQ scores for a random sample of subjects with low lead levels in their blood (sample 1) and another random
Alenkasestr [34]

Answer:

a. Null hypothesis: \mu_1 \leq \mu_2

Alternative hypothesis: \mu_1 >\mu_2

b. t=\frac{(92.88 -86.90)-(0)}{\sqrt{\frac{15.34^2}{78}}+\frac{8.99^2}{21}}=2.282

c. p_v =P(t_{97}>2.287) =0.0122

So with the p value obtained and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (Low Blood Lead level) is significantly higher than the mean for the group 2 (High Blood Lead level).  

Step-by-step explanation:

a. State and label the null and alternative hypotheses.

The system of hypothesis on this case are:

Null hypothesis: \mu_1 \leq \mu_2

Alternative hypothesis: \mu_1 >\mu_2

Or equivalently:

Null hypothesis: \mu_1 - \mu_2 \leq 0

Alternative hypothesis: \mu_1 -\mu_2>0

Our notation on this case :

n_1 =78 represent the sample size for group 1

n_2 =21 represent the sample size for group 2

\bar X_1 =92.88 represent the sample mean for the group 1

\bar X_2 =86.90 represent the sample mean for the group 2

s_1=15.34 represent the sample standard deviation for group 1

s_2=8.99 represent the sample standard deviation for group 2

b. State the value of the test statistic.

And the statistic is given by this formula:

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{\sqrt{\frac{s^2_1}{n_1}}+\frac{s^2_2}{n_2}}

Where t follows a t distribution with n_1+n_2 -2 degrees of freedom. If we replace the values given we have:

t=\frac{(92.88 -86.90)-(0)}{\sqrt{\frac{15.34^2}{78}}+\frac{8.99^2}{21}}=2.282

Now we can calculate the degrees of freedom given by:

df=78+21-2=97

c. Find either the critical value(s) and draw a picture of the critical region(s) or find the P-value for this test. Indicate which method you are using: ( CIRCLE ONE: Critical value / P-value )

Method used: P value

And now we can calculate the p value using the altenative hypothesis, since it's a right tail test the p value is given by:

p_v =P(t_{97}>2.287) =0.0122

So with the p value obtained and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (Low Blood Lead level) is significantly higher than the mean for the group 2 (High Blood Lead level).  

6 0
3 years ago
Could somebody please help me??
solniwko [45]

Answer:

She didn't make a mistake

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
A ping pong ball is released from a height of 60 centimeters (cm) and bounces to a height that is 3/4 the previous height. What
Oduvanchick [21]

Answer:

H = 60(3/4)^x

Step-by-step explanation:

After each bounce, the height it reach is 3/4 the previous one.

Let the height of nth bounce be denoted as h_n and the first bounce is h_1.

We are given that h_1 = 60 cm. Following the rule in the problem, we get:

h_2 = (3/4)h_1 = (3/4)60

h_3 = (3/4)h_2 = (3/4)*(3/4)60 = 60(3/4)^2

h_4 = (3/4)h_3 = (3/4)*60(3/4)^2= 60(3/4)^3

We see that h_n = 60(3/4)^n is the formula for the height for the nth bounce. Therefore, H = 60(3/4)^x is the answer.

I hope this helps! :)

8 0
3 years ago
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