Answer:The cost of one month of game-play =$20
Step-by-step explanation:
Let the cost of one month of gameplay be x
Then cost of game-play bought by Angie =3x.....(1)
and Then cost of game-play bought by Kenny=4x......(2)
Cost of each software package =$50......(3)
The the total cost =240= sum of costs of software bought by both of them and game-play)=50+50+3x+4x
⇒240=100+7x.......→(by adding like terms)
⇒140=7x⇒x=20.....→( dividing both sides by 7 )
∴the cost of one month of game-play =$20
Answer:
To obtain $ 100 in simple interest with a rate of 1.5%, Katie must deposit $ 6,666.66.
Step-by-step explanation:
Given that Katie wants to know how much she needs to deposit into a two year CD account in order to earn $ 100 in simple interest, knowing that the account currently has a 1.5% interest rate, the following calculation must be performed:
X x 0.015 = 100
X = 100 / 0.015
X = 6,666.66
6,666.66 x 1.015 = 6,766.66
Thus, to obtain $ 100 in simple interest with a rate of 1.5%, Katie must deposit $ 6,666.66.
It’s c since the line goes down 5 and the y intercept is 3 so it would be y=-5x+3
Answer:
20 gallons
Step-by-step explanation:
105/15=7
7*20=140
Answer:
y=t−1+ce
−t
where t=tanx.
Given, cos
2
x
dx
dy
+y=tanx
⇒
dx
dy
+ysec
2
x=tanxsec
2
x ....(1)
Here P=sec
2
x⇒∫PdP=∫sec
2
xdx=tanx
∴I.F.=e
tanx
Multiplying (1) by I.F. we get
e
tanx
dx
dy
+e
tanx
ysec
2
x=e
tanx
tanxsec
2
x
Integrating both sides, we get
ye
tanx
=∫e
tanx
.tanxsec
2
xdx
Put tanx=t⇒sec
2
xdx=dt
∴ye
t
=∫te
t
dt=e
t
(t−1)+c
⇒y=t−1+ce
−t
where t=tanx
