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WARRIOR [948]
3 years ago
12

Simplify the expression. 4y + 3( y+1) + 2 (x + 5)

Mathematics
1 answer:
Alik [6]3 years ago
5 0

Answer:

4y + 5x + 13

Step-by-step explanation:

4y + 3(y + 1) + 2(x+5)

Distribute

4y + 3y + (3 x 1) + 2x + (2 x 5)

4y + 3y + 3 + 2x + 10

Combine like terms

4y + 5x + 13

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Step-by-step explanation:

y = ax² + bx + c

The discriminant D = b² - 4ac tells the types of roots the equation has.

If D < 0 , then quadratic equation has no real roots, has two imaginary roots.

If D = 0 , then quadratic equation has one real root.

If D > 0 , then quadratic equation has two distinct real roots.

~~~~~~~~~~~~

x² + 5x - 4

a = 1, b = 5, c = - 4

<em>D </em>= 5² - 4(1)(- 4) = 25 + 16 =<em> 41</em>

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