SOLUTION
From the given data the mean is 62 and standard deviation is 4
It is required to find the probability that a data value is between 57 and 62
That is:

The z scores is calculated using:

Using the x values it follows:

Also,

Thus the required probability is:
![P(-1.25The proability is:[tex]P(-1.25This can be expressed as percentage as:[tex]P(-1.25\lt z\lt0.75)=66.8\%](https://tex.z-dn.net/?f=P%28-1.25The%20proability%20is%3A%5Btex%5DP%28-1.25This%20can%20be%20expressed%20as%20percentage%20as%3A%5Btex%5DP%28-1.25%5Clt%20z%5Clt0.75%29%3D66.8%5C%25)
Therefore the correct option is C
Answer: 0.31
Step-by-step explanation:
Let A denotes the event that the students report drinking alcohol and B denotes the students report using some type of tobacco product .
Given : P(A) =0.84 ; P(B)=0.33 and P(A∪B)=0.86
We know that 
Then, the probability that the student both drunk alcohol and used tobacco in the past month is given by :-

Hence, the probability that the student both drunk alcohol and used tobacco in the past month = 0.31
Answer:
1. 100 1. 150 1. 1
2.45 2. 800
Step-by-step explanation:
1. 25% * 400 = 0.25 * 400 =
* 400 = 100
2. 50% * 90 = 45
1. 75% * 200 = 0.75 * 200 = 3/4 * 200 = 150
2. 10% * 8000 = 0.1 * 8000 = 800
1. 5% * 20 = 0.05 * 20 = 1
They are both behind the decimal, they are both a decimal, they can both be turned into a fraction, and they both have a six
Answer:
$3.50
Step-by-step explanation:
2+2x=9
2x=7
x=3.5
$3.50