All categories

3 years ago

Which expression represents the output when the input is m?

Mathematics

1 answer:

Tresset [83]3 years ago

3 0

Uh can you show the problems? Because I wouldn’t be able to answer your question if you don’t show me the expressions

You might be interested in

How is everyone doing

m_a_m_a [10]

Answer:good u :)

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Jimmy made a trip to the ferry office and back. The trip there took two hours and the trip back took three hours. He averaged 20

sukhopar [10]

Answer:

60 mph

Step-by-step explanation:

We don't know how far Jimmy drives in each direction. Let this distance be d. Then, d = rate * time, and d = r(2 hours) (where r represents his speed while driving to the ferry).

But it's also true that d = (r - 20 mph)(3 hours).

Equating d = r(2 hours) and d = (r - 20 mph)(3 hours), we get:

r(2) = (r - 20)(3), or 2r = 3r - 60.

Subtracting 2r from both sides yields 0 = r - 60, so that r = 60 mph.

Jimmy averaged 60 mph on the outbound trip.

6 0

4 years ago

How do you write the equation in point slope form given slope=8, passing through (4,-1)?

xxMikexx [17]

Point slope form, y-y1 = m(x-x1)

Here, y1 = -1, x1 = 4, m=8

so, it would be: (y+1) = 8(x-4)

8 0

3 years ago

Read 2 more answers

The length of a rectangle is 5m less than three times the width, and the area of the rectangle is 50m^(2). Find the dimensions o

Ilia_Sergeevich [38]

Answer:

The width is 5m and the length is 10m.

Step-by-step explanation:

Rectangle:

Has two dimensions: Width(w) and length(l).

It's area is:

$A = w*l$

The length of a rectangle is 5m less than three times the width

This means that $l = 3w - 5$

The area of the rectangle is 50m^(2)

This means that $A = 50$ . So

$A = w*l$

$50 = w*(3w - 5)$

$3w^{2} - 5w - 50 = 0$

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

In this question:

$3w^{2} - 5w - 50 = 0$

$a = 3, b = -5, c = -50$

$\bigtriangleup = (-5)^{2} - 4*3*(-50) = 625$

$w_{1} = \frac{-(-5) + \sqrt{625}}{2*3} = 5$

$w_{2} = \frac{-(-5) - \sqrt{625}}{2*3} = -3.33$

Dimension must be positive result, so

The width is 5m(in meters because the area is in square meters).

Length:

$l = 3w - 5 = 3*5 - 5 = 10$

The length is 10 meters

6 0

3 years ago

What is the solution to this system of equations?

Semenov [28]

Answer:

Step-by-step explanation:

y=2x²+2x+1.... i

y=2x+3......... ii

Equating i and ii,

2x²+2x+1=2x+3

2x²+1-3=0

2x²-2=0

x²-1=0

x=1 or -1.

From ii, if x=1,y=5

If x=-1, y=1.

The points are (-1,1) and (1,5)

4 0

4 years ago