This is just a reflection. Not sure what your question is so I’ll just explain reflections. Reflections are flipping a shape across that certain line. Here, it is the X axis. What I usually do is see how far away each point is away from the (line of reflection) x axis. For example, G is 5 points away from the x axis, so the reflection of G is also 5 points away from the x axis. This works with any point of the shape. Hope this helped!
I’m assuming ‘dives further’ means to go directly down
the angle of elevation of the ship from the submarine is equal to the angle of depression of the submarine from the ship, if we assume the sea level is perpendicular to ‘directly down’.
let both of these angles to be = $ when the submarine is at A and ¥ when the submarine is at B (excuse the lack of easily accessible variables as keys)
then this become a simple trig problem:
A)
Let O be the position of of the ship, and C be the original position of the submarine.
therefore, not considering direction
|OC| = 1.78km = 1780m
|CA| = 45m
these are the adjacent and opposite sides of a right angled triangle.
But tan($) = opp/adj = |CA|/|OC| = 45/1780
therefore $ = arctan(45/1780) which is roughly 1.45 degrees,
B)
similarly, noting that |CB| = |CA| + |AB| = 45 + 62 = 107m
tan(¥) = 107/1780
¥ = arctan(107/1780) which is roughly 3.44 degrees
Answer:
y*(x+2)=k
so y= k/(x+2)
Step-by-step explanation:
First, we need to know how much the car depreciates each year. Multiply the price of the car by the percentage.
We can turn 9% into a decimal by moving the decimal point two places to the right.
9% = .09
24500 * .09 = 2205
Multiply the product by the amount of years you want to predict the price at.
2205 * 10 = 22050
Subtract that from the original price of the car.
24500 - 22050 = 2450
The value of a 10 year old car that costs $24500 and depreciates 9% every year will cost $2450.
