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2 years ago

PLEASEEEE HELLP ON A TIMER 15 MINS LEFT

Mathematics

1 answer:

emmainna [20.7K]2 years ago

8 0

Answer: D.

Step-by-step explanation: you find the ratio of the other lengths, then apply that ratio to the length of DC. Pls mark as brainliest?

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Use the drawing tools to form the correct answers on the graph.

SSSSS [86.1K]

Answer:

(-2,-12), (-1,-6), (0,-3) and (1,-3/2)

Step-by-step explanation:

x g(x)

-2 -3(1/2)^-2 = -12

-1 -3(1/2)^-1 = -6

0 -3(1/2)^0 = -3

1 -3(1/2)^1 = -3/2

Now, making the graph we will plot

(-2,-12), (-1,-6), (0,-3) and (1,-3/2)

Hope this helps!!

8 0

3 years ago

What is the length of missing side b in the figure below?

Anna11 [10]

According to the theory
b^2 = (13)^2 - (7)^2
b^2 = 169 - 49 = 120
b= root(120)
b= 10.95 cm

4 0

3 years ago

Read 2 more answers

1-2n) - 7n(12-2) simplify this and show work

Natasha2012 [34]

For this case we must simplify the following expression:

$(1-2n) -7n (12-2) =$

We solve the operation of the second parenthesis, taking into account that different signs are subtracted and the sign of the major is placed:

$(1-2n) -7n (10) =$

We multiply:

$(1-2n) -70n =$

We eliminate the parentheses:

$1-2n-70n =$

We add similar terms, taking into account that equal signs are added and the same sign is placed:

$1-72n$

Answer:

The simplified expression is: $1-72n$

5 0

3 years ago

Please help am stuck on this

Marina86 [1]

Answer:

-3,-2,-1,0,1,2,3,4,5

8 0

3 years ago

Read 2 more answers

Find the particular solution of the differential equation that satisfies the initial condition(s). f ''(x) = x−3/2, f '(4) = 1,

sweet [91]

Answer:

Hence, the particular solution of the differential equation is $y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x$ .

Step-by-step explanation:

This differential equation has separable variable and can be solved by integration. First derivative is now obtained:

$f'' = x - \frac{3}{2}$

$f' = \int {\left(x-\frac{3}{2}\right) } \, dx$

$f' = \int {x} \, dx -\frac{3}{2}\int \, dx$

$f' = \frac{1}{2}\cdot x^{2} - \frac{3}{2}\cdot x + C$ , where C is the integration constant.

The integration constant can be found by using the initial condition for the first derivative ( $f'(4) = 1$ ):

$1 = \frac{1}{2}\cdot 4^{2} - \frac{3}{2}\cdot (4) + C$

$C = 1 - \frac{1}{2}\cdot 4^{2} + \frac{3}{2}\cdot (4)$

$C = -1$

The first derivative is $y' = \frac{1}{2}\cdot x^{2}- \frac{3}{2}\cdot x - 1$ , and the particular solution is found by integrating one more time and using the initial condition ( $f(0) = 0$ ):

$y = \int {\left(\frac{1}{2}\cdot x^{2}-\frac{3}{2}\cdot x -1 \right)} \, dx$

$y = \frac{1}{2}\int {x^{2}} \, dx - \frac{3}{2}\int {x} \, dx - \int \, dx$

$y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x + C$

$C = 0 - \frac{1}{6}\cdot 0^{3} + \frac{3}{4}\cdot 0^{2} + 0$

$C = 0$

Hence, the particular solution of the differential equation is $y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x$ .

5 0

3 years ago