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Trava [24]
2 years ago
7

PLEASEEEE HELLP ON A TIMER 15 MINS LEFT

Mathematics
1 answer:
emmainna [20.7K]2 years ago
8 0

Answer: D.

Step-by-step explanation: you find the ratio of the other lengths, then apply that ratio to the length of DC. Pls mark as brainliest?

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Use the drawing tools to form the correct answers on the graph.
SSSSS [86.1K]

Answer:

(-2,-12), (-1,-6), (0,-3) and (1,-3/2)

Step-by-step explanation:  

x     g(x)

-2    -3(1/2)^-2 = -12

-1     -3(1/2)^-1 = -6

0     -3(1/2)^0 = -3

1      -3(1/2)^1 = -3/2

Now, making the graph we will plot

(-2,-12), (-1,-6), (0,-3) and (1,-3/2)

Hope this helps!!

8 0
3 years ago
What is the length of missing side b in the figure below?
Anna11 [10]
According to the theory
b^2 = (13)^2 - (7)^2
b^2 = 169 - 49 = 120
b= root(120)
b= 10.95 cm
4 0
3 years ago
Read 2 more answers
1-2n) - 7n(12-2) simplify this and show work​
Natasha2012 [34]

For this case we must simplify the following expression:

(1-2n) -7n (12-2) =

We solve the operation of the second parenthesis, taking into account that different signs are subtracted and the sign of the major is placed:

(1-2n) -7n (10) =

We multiply:

(1-2n) -70n =

We eliminate the parentheses:

1-2n-70n =

We add similar terms, taking into account that equal signs are added and the same sign is placed:

1-72n

Answer:

The simplified expression is: 1-72n

5 0
3 years ago
Please help am stuck on this
Marina86 [1]

Answer:

-3,-2,-1,0,1,2,3,4,5

8 0
3 years ago
Read 2 more answers
Find the particular solution of the differential equation that satisfies the initial condition(s). f ''(x) = x−3/2, f '(4) = 1,
sweet [91]

Answer:

Hence, the particular solution of the differential equation is y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x.

Step-by-step explanation:

This differential equation has separable variable and can be solved by integration. First derivative is now obtained:

f'' = x - \frac{3}{2}

f' = \int {\left(x-\frac{3}{2}\right) } \, dx

f' = \int {x} \, dx -\frac{3}{2}\int \, dx

f' = \frac{1}{2}\cdot x^{2} - \frac{3}{2}\cdot x + C, where C is the integration constant.

The integration constant can be found by using the initial condition for the first derivative (f'(4) = 1):

1 = \frac{1}{2}\cdot 4^{2} - \frac{3}{2}\cdot (4) + C

C = 1 - \frac{1}{2}\cdot 4^{2} + \frac{3}{2}\cdot (4)

C = -1

The first derivative is y' = \frac{1}{2}\cdot x^{2}- \frac{3}{2}\cdot x - 1, and the particular solution is found by integrating one more time and using the initial condition (f(0) = 0):

y = \int {\left(\frac{1}{2}\cdot x^{2}-\frac{3}{2}\cdot x -1  \right)} \, dx

y = \frac{1}{2}\int {x^{2}} \, dx - \frac{3}{2}\int {x} \, dx - \int \, dx

y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x + C

C = 0 - \frac{1}{6}\cdot 0^{3} + \frac{3}{4}\cdot 0^{2} + 0

C = 0

Hence, the particular solution of the differential equation is y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x.

5 0
3 years ago
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