For this case we have the following equation $e ^ {3x} = 12$ , from which we must clear the value of the variable "x" and round to the nearest hundredth. To do this, we must apply properties of neperian and exponential logarithms. By definition:

$ln (e ^ x) = x$

So:

$e ^ {3x} = 12$ We apply Neperian logarithm to both sides:

$ln (e^{3x}) = ln (12)\\3x = ln (12)$

We divide between "3" both sides of the equation:

$\frac {3x} {3} = \frac {ln (12)} {3}\\x = \frac {ln (12)} {3}\\x = 0.828302217$

Rounding out the nearest hundredth we have:

$x = 0.83$

Answer:

$x = 0.83$

3 0

3 years ago

Read 2 more answers

What is 9.09 repeating as a fraction?

Alborosie

9 1/11
or 100/11
they are both the same, it just depends on how the class wants you to write it

3 0

3 years ago

Which relation is a function?

uysha [10]

B, because nothing repeats.

4 0

2 years ago

What is the value of -2.12 - 6.84 + 4.19?

hodyreva [135]

Answer:

Try 8.91

Step-by-step explanation:

6.84+4.19=11.03-2.12=8.91

8 0

2 years ago