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Tom [10]
3 years ago
12

A paintball court charges an initial entrance fee plus a fixed price per ball. The variable ppp models the total price (in dolla

rs) as a function of nnn, the number of balls used. p=0.80n+5.50p=0.80n+5.50p, equals, 0, point, 80, n, plus, 5, point, 50 What is the entrance fee? \$
Mathematics
2 answers:
Tems11 [23]3 years ago
8 0

Answer: the answer is 8.

Step-by-step explanation:

DaniilM [7]3 years ago
7 0

Answer:

$5.50

Step-by-step explanation:

The function we are given is

p = 0.80n + 5.50,

where n is the number of balls.

Multiplying this variable by 0.80 means $0.80 will be the cost per ball.  The additional amount added to the variable in the function, 5.50, will be the entrance fee.

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Vedmedyk [2.9K]

Answer:

k

Step-by-step explanation:

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7 0
2 years ago
Martin is offered an investment where for $6,000 ​today, he will receive $6,180 in one year. He decides to borrow $6,000 from th
nirvana33 [79]

Answer:

The correct answer is D. 3 % p. a .

Step-by-step explanation:

For the investment offered, Martin is supposed to get $180 as an interest ($6,180 - $6,000).

Now Martin is borrowing $6,000 from the bank to make this investment. He should be charged $180, so that he breaks even on investment.

Thus using the formula:

Interest= Principal × Time ( per annum) × \frac{Interest rate}{100} ; (Here simple and compound interest are same as the sum borrowed is to be charged for a single year)

⇒ 180 = \frac{6000}{100} × 1 × Interest rate

⇒ 180 = 60 × Interest rate

⇒ Interest rate = 3

Thus the correct answer is 3% per annum.

3 0
3 years ago
Smooth Operator
eduard

Answer:1,240 minutes or 20 1/3 hours.

Step-by-step explanation: there are 31 days in january so 40 x 31=2140

8 0
2 years ago
Write an equation that represents the pattern in the table
Slav-nsk [51]
Y=3x

explain
4x3=12 , 5x3=15 , 6x3=18 ,.......
8 0
2 years ago
Find 2 numbers a and b such that (a-b)^2 < (a+b)(a-b)< (a+b)^2 Find two numbes a and b such that this is not true
Svet_ta [14]

Suppose for the moment that the inequality holds for all a,b:

(a-b)^2

Expanding everything gives

a^2-2ab+b^2

\implies-ab

In particular, the inequality says that -ab for any choice of a,b. But if a and b>0, then -ab>0 while ab.

So one possible choice of a,b could be a=-1 and b=1. Then we get

(-1-1)^2=4

(-1+1)(-1-1)=2

(-1+1)^2=0

but clearly it's not true that 4.

8 0
3 years ago
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