In order to estimate the mean amount of time computer users spend on the internet each month, how many computer users must be s
urveyed in order to be 9595% confident that your sample mean is within 1010 minutes of the population mean? Assume that the standard deviation of the population of monthly time spent on the internet is 221221 min. What is a major obstacle to getting a good estimate of the population mean? Use technology to find the estimated minimum required sample size.
We have that for 95% of confident, the value of z has a value of 1.96 (attached table about it), they also mention the margin of error (E) that is 10 and finally the standard deviation (sd) that has a value of 221.
take 6 away from 8 and you get 2. That is your numerator. If you had 10 to begin with, that is your denominator so it will look like 2/1. IF SIMPLIFIED IT IS 1/5.
