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MAXImum [283]
3 years ago
9

In order to estimate the mean amount of time computer users spend on the internet each​ month, how many computer users must be s

urveyed in order to be 9595​% confident that your sample mean is within 1010 minutes of the population​ mean? Assume that the standard deviation of the population of monthly time spent on the internet is 221221 min. What is a major obstacle to getting a good estimate of the population​ mean? Use technology to find the estimated minimum required sample size.
Mathematics
1 answer:
levacccp [35]3 years ago
7 0

Answer:

1877 computer users

Step-by-step explanation:

We have that for 95% of confident, the value of z has a value of 1.96 (attached table about it), they also mention the margin of error (E) that is 10 and finally the standard deviation (sd) that has a value of 221.

We apply the following formula:

n = [z * sd / E] ^ 2

replacing:

n = [1.96 * 221/10] ^ 2

n = 1876.27

that is, the minimum sample size is 1877

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A cone-shaped pile of sawdust has a base diameter of 38 feet, and is 14 feet tall. Find the volume of the pile
Romashka-Z-Leto [24]

Answer:

Given: Diameter of cone = 38 feet and height of cone = 14 feet.

Volume of cone V with radius r is one-third the area of the base B times the height h.

i,e  V = \frac{1}{3} B \cdot h = \frac{1}{3} \pi r^2h  ......[1]

,where B = \pi r^2

First find the radius(r);

Using Diameter(D) = 2r

38 =2r

Divide both side by 2 we get;

\frac{38}{2} =\frac{2r}{2}

Simplify:

19 = r

or r =19 feet

Now, substitute the value of r = 19 feet and h = 14 feet in [1]    [ Use value of  \pi = \frac{22}{7} ]

then, we have:

V = \frac{1}{3} \pi r^2h = \frac{1}{3} \cdot  \frac{22}{7} \cdot (19)^2 \cdot (14)

or

V = =\frac{1}{3}\cdot 22 \cdot 19 \cdot 19 \cdot  2 = \frac{22 \cdot 19 \cdot 19 \cdot 2}{3}

or

V = \frac{15884}{3} =5,294.66667 ≈ 5,294.67 cubic feet.

therefore, the volume of pile is; ≈ 5,294.67 cubic feet.


4 0
3 years ago
1. Find the capacity in litres of a bucket 24cm in
Sav [38]

Answer:

6.36l

Step-by-step explanation:

We compute first the volume:

V=pi×h/3×(R²+r²+rR), where h=20cm is the height, R=24/2=12cm is the top radius, r=16/2=8cm is the bottom radius.

We get: V=pi×20/3(12²+8²+12×8)=

20×pi/3(144+64+96)cm³

V=20×pi/3×304=6363.73cm³

In dm³ we have (divide by 1000) V=6.36dm³

By definition, 1dm³=1l, so the capacity is 6.36l

8 0
4 years ago
For the function​ below, find a formula for the upper sum obtained by dividing the interval [a comma b ][a,b] into n equal subin
Vlad [161]

Answer:

See below

Step-by-step explanation:

We start by dividing the interval [0,4] into n sub-intervals of length 4/n

[0,\displaystyle\frac{4}{n}],[\displaystyle\frac{4}{n},\displaystyle\frac{2*4}{n}],[\displaystyle\frac{2*4}{n},\displaystyle\frac{3*4}{n}],...,[\displaystyle\frac{(n-1)*4}{n},4]

Since f is increasing in the interval [0,4], the upper sum is obtained by evaluating f at the right end of each sub-interval multiplied by 4/n.

Geometrically, these are the areas of the rectangles whose height is f evaluated at the right end of the interval and base 4/n (see picture)

\displaystyle\frac{4}{n}f(\displaystyle\frac{1*4}{n})+\displaystyle\frac{4}{n}f(\displaystyle\frac{2*4}{n})+...+\displaystyle\frac{4}{n}f(\displaystyle\frac{n*4}{n})=\\\\=\displaystyle\frac{4}{n}((\displaystyle\frac{1*4}{n})^2+3+(\displaystyle\frac{2*4}{n})^2+3+...+(\displaystyle\frac{n*4}{n})^2+3)=\\\\\displaystyle\frac{4}{n}((1^2+2^2+...+n^2)\displaystyle\frac{4^2}{n^2}+3n)=\\\\\displaystyle\frac{4^3}{n^3}(1^2+2^2+...+n^2)+12

but  

1^2+2^2+...+n^2=\displaystyle\frac{n(n+1)(2n+1)}{6}

so the upper sum equals

\displaystyle\frac{4^3}{n^3}(1^2+2^2+...+n^2)+12=\displaystyle\frac{4^3}{n^3}\displaystyle\frac{n(n+1)(2n+1)}{6}+12=\\\\\displaystyle\frac{4^3}{6}(2+\displaystyle\frac{3}{n}+\displaystyle\frac{1}{n^2})+12

When n\rightarrow \infty both \displaystyle\frac{3}{n} and \displaystyle\frac{1}{n^2} tend to zero and the upper sum tends to

\displaystyle\frac{4^3}{3}+12=\displaystyle\frac{100}{3}

8 0
4 years ago
Which statement describes the function y=ax^n when a=1 and n is odd?
julsineya [31]
ANSWER

B. The graph is symmetric about the origin

EXPLANATION.

The given function is

y = a {x}^{n}

When a=1,

y = {x}^{n}

Let,

f(x)= {x}^{n}

f(-x)= {( - x)}^{n}

Since n is odd,

f(-x)=-{( x)}^{n}

\Rightarrow f(-x)=-f(x)

This implies that, the function

y={x}^{n}

is symmetric with respect to origin.

The correct answer is B
5 0
3 years ago
Read 2 more answers
How do I calculate the arc length of y = x^3/6 + 4x^2
Allushta [10]
The formula for arc length is...

arc length = radius • central angle
6 0
3 years ago
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