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telo118 [61]
3 years ago
15

Whats the answer to x+3/4=5/8

Mathematics
2 answers:
Lerok [7]3 years ago
7 0

Answer:

-1/8 = x

Step-by-step explanation:

turn the 3/4 into 6/8 so the denominators match on both sides

subtract 6/8 from both sides

the right side is now -1/8

x equals -1/8

sorry if it does it make sense.. ^_^;;

anyanavicka [17]3 years ago
3 0

Answer:

Exact Form:

x=−18x=-18

Decimal Form:

x=−0.125x=-0.125

Step-by-step explanation:

Move all terms not containing xx to the right side of the equation

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Boa tarde gentiii Abaixo aparecem quatro sequências. Defina cada uma delas como RECURSIVA ou NÃO RECURSIVA. a) (5, 7, 9, 11, 13,
marusya05 [52]

Answer:

a) (5, 7, 9, 11, 13, 15, 17, 19, ...) Recursivo

b) (1, 4, 9, 16, 25, 36, 49, 64, ...) Recursivo

c) (1, 8, 27, 64, ...) Recursivo

d) (2, 5, 8, 11, 14, 17, ...) Recursivo

Step-by-step explanation:

Uma função recursiva é aquela em que os termos subsequentes da função são calculados com base nos termos anteriores

O comportamento recursivo é exibido pelos objetos quando consiste em seguir as partes;

1) Uma base que é predefinida

2) Um processo ou etapa recursiva que produz termos subsequentes pela aplicação de certos processos

Para a série;

a) (5, 7, 9, 11, 13, 15, 17, 19, ...)

Aqui 5 é a base e os termos subsequentes são encontrados adicionando 2 ao termo anterior, portanto, é uma função recursiva

aₙ = aₙ₋₁ + 2

b) (1, 4, 9, 16, 25, 36, 49, 64, ...)

Aqui 1 é a base e os termos subsequentes são encontrados ao quadrado da soma da raiz do termo anterior e 1, portanto, é uma função recursiva

aₙ = (√ (aₙ₋₁) + 1) ²

c) (1, 8, 27, 64, ...)

Aqui 1 é a base e os termos subsequentes são encontrados elevando à potência de três a soma da raiz cúbica do termo anterior e 1, portanto, é uma função recursiva

aₙ = (∛ (aₙ₋₁) + 1) ³

d) (2, 5, 8, 11, 14, 17, ...)

Aqui 2 é a base e os termos subsequentes são encontrados adicionando 3 ao termo anterior, portanto, é uma função recursiva.

7 0
3 years ago
A photocopier can make 20 copies per minute. which equation can be used to find m, the number of minutes the copier takes to mak
Alex777 [14]

Answer:

It's Option'A' i.e 20m=75

Step-by-step explanation:

or,m=75/20

or,m=3.75

8 0
2 years ago
Can someone help me with a b and c please
abruzzese [7]

Answer:

c.in this 2014,396.12million pets were owned

3 0
3 years ago
A certain geneticist is interested in the proportion of males and females in the population who have a minor blood disorder. In
lord [1]

Answer:

95% confidence interval for the difference between the proportions of males and females who have the blood disorder is [-0.064 , 0.014].

Step-by-step explanation:

We are given that a certain geneticist is interested in the proportion of males and females in the population who have a minor blood disorder.

A random sample of 1000 males, 250 are found to be afflicted, whereas 275 of 1000 females tested appear to have the disorder.

Firstly, the pivotal quantity for 95% confidence interval for the difference between population proportion is given by;

                        P.Q. = \frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }  ~ N(0,1)

where, \hat p_1 = sample proportion of males having blood disorder= \frac{250}{1000} = 0.25

\hat p_2 = sample proportion of females having blood disorder = \frac{275}{1000} = 0.275

n_1 = sample of males = 1000

n_2 = sample of females = 1000

p_1 = population proportion of males having blood disorder

p_2 = population proportion of females having blood disorder

<em>Here for constructing 95% confidence interval we have used Two-sample z proportion statistics.</em>

<u>So, 95% confidence interval for the difference between the population proportions, </u><u>(</u>p_1-p_2<u>)</u><u> is ;</u>

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level

                                             of significance are -1.96 & 1.96}  

P(-1.96 < \frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} } < 1.96) = 0.95

P( -1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} } < {(\hat p_1-\hat p_2)-(p_1-p_2)} < 1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} } ) = 0.95

P( (\hat p_1-\hat p_2)-1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} } < (p_1-p_2) < (\hat p_1-\hat p_2)+1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} } ) = 0.95

<u>95% confidence interval for</u> (p_1-p_2) =

[(\hat p_1-\hat p_2)-1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }, (\hat p_1-\hat p_2)+1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }]

= [ (0.25-0.275)-1.96 \times {\sqrt{\frac{0.25(1-0.25)}{1000}+ \frac{0.275(1-0.275)}{1000}} }, (0.25-0.275)+1.96 \times {\sqrt{\frac{0.25(1-0.25)}{1000}+ \frac{0.275(1-0.275)}{1000}} } ]

 = [-0.064 , 0.014]

Therefore, 95% confidence interval for the difference between the proportions of males and females who have the blood disorder is [-0.064 , 0.014].

8 0
3 years ago
Can someone help me with this? Please-
lozanna [386]

Answer:

C

Step-by-step explanation:

8 0
3 years ago
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