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Eddi Din [679]
3 years ago
11

How do to soving problems in math what is a trick​

Mathematics
2 answers:
Alex3 years ago
8 0

Answer:

Two-Step Addition

Two-Step Subtraction

Subtracting from 1,000

Doubling and Halving

Multiplying by Powers of 2

Multiplying by 9

Multiplying Even Numbers by 5

Multiplying Odd Numbers by 5

Squaring a Two-Digit Number that Ends with 1

these all can help you

Step-by-step explanation:

elena-s [515]3 years ago
7 0

Answer there is no trick you just have to know your math  as in time tables division addition and subtraction

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A cone with a radius of 3" has a total area of 24π sq. in. Find the volume of the cone.
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The answer is 12π.

To get the volume of the cone, we need the height. The radius is given.

V = πr² × (h/3)

The total surface area of the cone is:
SA = πr² + πrl where r is radius and l is slant height

24π = π(3)² + π(3)(l)
24π = 9π + 3πl
24π - 9π = 3πl
15π = 3πl
l = 15π / 3π
l = 5

Using Phytagoras, we can calculate the height of the cone:
l² = h² + r²
5² = h² + 3²
25 - 9 = h²
h = √16
h = 4

Therefore the volume is:
V = π(3)² × (4 / 3)
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5 0
3 years ago
Read 2 more answers
I have no idea!! Please help!!!
Ber [7]
The area of a traingle is \frac{1}{2}bh
So we need to know the base and the height
To work out the sides of a right angle triangle we can use a²+b²=c
c is the hypotenuse and a and b are the other sides
Because this triangle is isoceles we know that a and b are the same

a²+b²=c²
a²+a²=c²
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2a²=(x√6)²
2a²=(x√6)(x√6)
2a²=x²+x√6+x√6+6
2a²=x²+x√6+x√6+6
a²=\frac{x^{2}+x \sqrt{6}+x \sqrt{6}+6 }{2}
a=\sqrt{\frac{x^{2}+x\sqrt{6}+x\sqrt{6}+6}{2}}

A=\frac{1}{2}bh
A=\frac{1}{2}a*a
A=\frac{1}{2}×\sqrt{\frac{x^{2}+x\sqrt{6}+x\sqrt{6}+6}{2}}×\sqrt{\frac{x^{2}+x\sqrt{6}+x\sqrt{6}+6}{2}}
A=\frac{1}{2}×\frac{x^{2}+x \sqrt{6}+x \sqrt{6}+6 }{2}
A=\frac{x^{2}+x \sqrt{6}+x \sqrt{6}+6 }{4}
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3 years ago
Y = 1/2x -4 plz show the graph, I really need to know! But it's 8th grade math!
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Answer:

(-4, 8)

Step-by-step explanation:

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3 years ago
Most cells in the body have only half the amount of chromosomes
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I did this one

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