7. There are approximately 1.2 x 108 households

A: What are the solutions to the quadratic equation x2+9=0? B: What is the factored form of the quadratic expression x2+9? Selec

Paraphin [41]

Answer:

A. The solutions are $x=3i,\:x=-3i$ .

B. The factored form of the quadratic expression $x^2+9=(x-3i)(x+3i)$

Step-by-step explanation:

A. To find the solutions to the quadratic equation $x^2+9=0$ you must:

$\mathrm{Subtract\:}9\mathrm{\:from\:both\:sides}\\\\x^2+9-9=0-9\\\\\mathrm{Simplify}\\\\x^2=-9\\\\\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}\\\\x=\sqrt{-9},\:x=-\sqrt{-9}$

$x=\sqrt{-9} = \sqrt{-1}\sqrt{9}=\sqrt{9}i=3i\\\\x=-\sqrt{-9}=-\sqrt{-1}\sqrt{9}=-\sqrt{9}i=-3i$

The solutions are:

$x=3i,\:x=-3i$

B. Two expressions are equivalent to each other if they represent the same value no matter which values we choose for the variables.

To factor $x^2+9$ :

First, multiply the constant in the polynomial by $i^2$ where $i^2$ is equal to -1.

$x^2+9i^2$

Since both terms are perfect squares, factor using the difference of squares formula

$a^2-i^2=(a+i)(a-i)$

$x^2+9=x^2+9i^2=\left(-3i+x\right)\left(3i+x\right)$

5 0

3 years ago

The least common multiple of two numbers is 3780, and the greatest common divisor is 18. given that one of the numbers is 180, w

garri49 [273]

To solve these GCF and LCM problems, factor the numbers you're working with into primes:
3780 = 2*2*3*3*3*5*7
180 = 2*2*3*3*5
We know that the LCM of the two numbers, call them A and B, = 3780 and that A = 180. The greatest common factor of 180 and B = 18 so B has factors 2*3*3 in common with 180 but no other factors in common with 180. So, B has no more 2's and no 5's
Now, LCM(180,B) = 3780. So, A or B must have each of the factors of 3780. B needs another factor of 3 and a factor of 7 since LCM(A,B) needs for either A or B to have a factor of 2*2, which A has, and a factor of 3*3*3, which B will have with another factor of 3, and a factor of 7, which B will have.
So, B = 2*3*3*3*7 = 378.

8 0

2 years ago

Hlp me pls identify inverse operations

Anika [276]

Inverse operation is an operation that undoes what was done by the previous operation. Take this simple addition problem 5+2=7. If we want to reverse the addition, we just subtract 7-2=5 and we are back where we started. You do the same for multiplication and division.

3 0

2 years ago

How do you solve -10+2y=7

Eva8 [605]

Answer

y = $\frac{17}{2}$

Step-by-step explanation:

-10 + 2y = 7

Add 10 to both sides of the equation

2y = 7 + 10

Add 7 and 10

2y = 17

divide each term in 2y=17 by 2

$\frac{2y }{2} = \frac{17}{2}$

Divide y by 7

y = $\frac{17}{2}$

Hope this helps

5 0

3 years ago

The product of two positive consecutive odd integers is 2703. What are the positive numbers?

liberstina [14]

Answer:

The positive numbers are 51 and 53

Step-by-step explanation:

Let first odd integer be x and another odd integer is (x+2).

According to the given condition,

The product of two positive consecutive odd integers is 2703 i.e.

x(x+2) = 2703

$x^2+2x-2703=0$

It is a quadratic equation. It can be solved as follows :

x = 51 and x = -53

Neglecting negative sign,

The first number = 51

Another number =(51+2) = 53

Hence, the positive numbers are 51 and 53.

7 0

2 years ago