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il63 [147K]
3 years ago
5

Eleven graduate students have applied for three available teaching assistantships. In how many ways can these assistantships be

awarded among the applicants if the group of applicants includes six men and five women and it is stipulated that at least one woman must be awarded an assistantship?
Mathematics
2 answers:
kykrilka [37]3 years ago
8 0
3men, 1 women. for the first 2. and 2 men, 1 women for the third
KATRIN_1 [288]3 years ago
7 0
The number of combinations, regardless of gender, is 11C3.
The number of combinations of men only is 6C3.
Therefore the required number of combinations is given by:
11C3 - 6C3 = 145
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Sindrei [870]
If i did the math correctly one number is 50
19 has two factors: 1, 19
21 has four factors: 1, 3, 7, 21
23 has two factors: 1, 23
And we need a number that has more than four factors and is greater than 25.
Factors of 50- 1, 2, 5, 10, 25, 50
50has six factors and is greater than 25.

4 0
3 years ago
Factorise B square minus 25 ​
GuDViN [60]

Answer: (b+5)(b-5)

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
The length of a rectangle is 10 inches more than 2 times the width. If the area of the rectangle is 28 square
xxTIMURxx [149]

Answer:≥2

Step-by-step explanation:

First, we need to translate the problem into algebraic expressions and equations:

[length][is][ten inches more than][twice the width]

⟹[][=][10+][2×]

⟹=10+2

==(10+2)()=22+10

[Area][is at least][28]

[][≥][28]

⟹≥28

Putting these together, we have a quadratic inequality:

22+10≥28

The most straightforward way [I know of] to solve this is to compare to zero, find the roots, and go from there:

22+10−28≥0

⟹2+5−14≥0

Finding the zeros using your favorite method — factoring, quadratic formula, etc. — yields zeros of  ={−7,2} .

Since the width of the rectangle can’t be negative, our solution involves  =2 . The graph of the quadratic function is concave up (due to the positive leading coefficient), meaning the function is non-negative for  ≤−7  or  ≥2  — giving us our solution,  ≥2 !

5 0
3 years ago
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