3 years ago

PLEASE HELP ME :( Solve N = 3pg^2 - 2pv for v.

Mathematics

1 answer:

BigorU [14]3 years ago

7 0

Answer:

v = $\frac{3pg^2-N}{2p}$

Step-by-step explanation:

Given

N = 3pg² - 2pv ( isolate term with v by subtracting 3pg² from both sides )

N - 3pg² = - 2pv ( multiply through by - 1 to clear the negatives )

3pg² - N = 2pv ( divide both sides by 2p )

$\frac{3pg^2-N}{2p}$ = v

You might be interested in

Write an inequality for the given description. The product of -5 and an unknown number increased by 15 is less than or equal to

sesenic [268]

Answer:

-5x +15 ≤ 20

Step-by-step explanation:

7 0

3 years ago

A railroad inspects 360 railcars. if 95% passed, how many cars passed the inspection?

Cloud [144]

The answer is 342cara

5 0

3 years ago

HEEELP

Drupady [299]

Answer: (c)

Step-by-step explanation:

Given

$f(x)=\dfrac{1}{x-3}\\\\g(x)=\sqrt{x+5}$

Here, $\sqrt{x+5}\ \text{is always greater than equal to 0}\\\Rightarrow x+5\geq 0\\\Rightarrow x\geq -5\quad \ldots(i)$

To get $f\left(g(x)\right)$ , replace $x$ in $f(x)$ by $g(x)\ \text{i.e. by}\ \sqrt{x+5}$

$\Rightarrow f\left(g(x)\right)=\dfrac{1}{\sqrt{x+5}-3}\\\\\text{Denominator must not be equal to 0}\\\\\therefore \sqrt{x+5}-3\neq0\\\Rightarrow \sqrt{x+5}\neq 3\\\Rightarrow x+5\neq 9\\\Rightarrow x\neq 4\quad \ldots(ii)$

Using $(i)$ and $(ii)$ it can be concluded that the domain of $f\left(g(x)\right)$ is all real numbers except 0.

Therefore, its domain is given by

$x\in [-5,4)\cup (4,\infty)$

Option (c) is correct.

5 0

3 years ago

Find the median of these numbers:4,2,7,4,3 *

sattari [20]

Answer:

The Median of those numbers is 4

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

There are 3/4 of a pizza left over from last night how many 1/8 portions are there

KiRa [710]

3/4 of the pizza is left

3/4 = 6/8

There are 6 "1/8" portions left

hope this helps

8 0

3 years ago