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2 years ago

7

PLEASE HELP ME :( Solve N = 3pg^2 - 2pv for v.

1 answer:

BigorU [14]2 years ago

7 0

Answer:

v = $\frac{3pg^2-N}{2p}$

Step-by-step explanation:

Given

N = 3pg² - 2pv ( isolate term with v by subtracting 3pg² from both sides )

N - 3pg² = - 2pv ( multiply through by - 1 to clear the negatives )

3pg² - N = 2pv ( divide both sides by 2p )

$\frac{3pg^2-N}{2p}$ = v

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VikaD [51]

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2 years ago

Simplify 5m-2(6m-5)+2<br><br>a. -7m-8<br>b. -7m+12<br>c. 17m+12<br>d. 17m-8

fgiga [73]

The answer is B. -7m+12.

First distribute the -2 to 6m and -5.

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5m+(-2*6m)+(-2*-5)+2

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After that, combine the like terms.

5m+-12m+10+2

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3 years ago

Help with pic please as siin as possibke SIMPLIFY....

Ratling [72]

Answer:

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Step-by-step explanation:

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2 years ago

Use the graph below to determine a1 and d for the sequence. graphed sequence showing point 1, negative 10, point 2, negative 7,

Sonja [21]

Answer:

$a_1=-10$

$d=3$

Step-by-step explanation:

we know that

In an <u><em>Arithmetic Sequence</em></u> the difference between one term and the next is a constant, and this constant is called the common difference (d)

In this problem we have the ordered pairs

$(1,-10),(2,-7),(3,-4),(4,-1),(5,2),(6,5)$

Let

$a_1=-10\\a_2=-7\\a_3=-4\\a_4=-1\\a_5=2\\a_6=5$

Find the difference between one term and the next

$a_2-a_1=-7-(-10)=3$

$a_3-a_2=-4-(-7)=3$

$a_4-a_3=-1-(-4)=3$

$a_5-a_4=2-(-1)=3$

$a_6-a_5=5-2=3$

The difference between one term and the next is a constant

This constant is the common difference

so

The sequence graphed is an Arithmetic Sequence

therefore

The first term is $a_1=-10$

The common difference is equal to $d=3$

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3 years ago

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Elena L [17]

Answer:

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Step-by-step explanation

Im not positive but theres a high chance its B

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2 years ago