3 years ago

PLEASE HELP ME :( Solve N = 3pg^2 - 2pv for v.

Mathematics

1 answer:

BigorU [14]3 years ago

7 0

Answer:

v = $\frac{3pg^2-N}{2p}$

Step-by-step explanation:

Given

N = 3pg² - 2pv ( isolate term with v by subtracting 3pg² from both sides )

N - 3pg² = - 2pv ( multiply through by - 1 to clear the negatives )

3pg² - N = 2pv ( divide both sides by 2p )

$\frac{3pg^2-N}{2p}$ = v

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