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3 years ago

7

ABBBAAA what is the a to b ratio?

1 answer:

Ede4ka [16]3 years ago

3 0

there are 4 A and 3 B.

so the ratio is 4 : 3

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What does x and y =??????

Kazeer [188]

Answer:

x=30. y=60

Step-by-step explanation:

DG is a straight segment so it sums to 180 degrees. ECG is a right angle so 90 degrees. The rest is described as 2x and x. So 3x=90 degrees. x=30. Eh is also a straight segment. since we know x, we know that ECD is 60 degrees. So y+y=120 degrees. 2y=120. y=60.

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3 years ago

I literally have no clue how to do this.

timurjin [86]

Answer:

Step-by-step explanation:

Sine is opposite divided by the hypotenuse.

sin(30) = 9/y

1/2 = 9/y

y = 18

Cosine is adjacent divided by the hypotenuse

cos(30) = x/18

$\frac{\sqrt{3} }{2}=x/18\\x=9\sqrt{3}=15.6$

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3 years ago

Help! Will give brainliest :D

miss Akunina [59]

Answer is:
Obtuse and isosceles

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3 years ago

Please help with all For 30 POINTS and BRAINLEST answer please and thanks p.s ignore if I got the first one wrong :)

Gnom [1K]

(2) 11x3 (3) 7x5 (4) (8+5)x9 (5) 12+3 (6) 5x2 (7) (6+4)x8 (8) 8 + 13 Message me for more information

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4 years ago

NGC is a hot air balloon in the sky from her spot on the ground. The angle of elevation from Angie to the balloon is 40°. If she

Goshia [24]

Answer:

The distance from hot air balloon to the ground $AC=50.1457 ft$ .

Step-by-step explanation:

Labelled diagram of given scenario is shown below.

Given that,

An angle of elevation of Hot air balloon by Angie is $40$ °.

When she stepped back $200 ft$ then angle of elevation was $10$ °.

Height of Angie is $5.5 ft$ .

To find: How far off the ground is a hot air balloon.

So, from figure

Height of Angie $(BC) = 5.5ft$

In triangle Δ $ABD$ ,

⇒ $tan {40\si {\degree}} = \frac{AB}{BD}$

⇒ $AB = tan (40) \times BD$ ....................(1)

Now, In triangle Δ $ABE$

⇒ $tan (10)= \frac{AB}{200+BD}$

⇒ $AB = tan(10)\times (200+BD)$

Here, substituting the value $AB$ from Equation (1) we get,

$tan(10)\times (200+BD)= tan(40)\times BD$

$tan(10)\times 200+tan(10)\times BD= tan(40)\times BD$

⇒ $BD\times (tan(40)-tan(10))=tan(10)\times 20$

⇒ $BD\times 0.6628 = 35.2654$

⇒ $BD = \frac{35.2654}{0.6628} =53.2067 ft$

Now, finding the value of $AB$ from equation (1)

$AB= tan(40)\times 53.2067=0.8391\times 53.2067$

$AB=44.6457 ft$

Therefore Length of $AC= AB+BC$ = $(44.6457 + 5.5) ft$

$AC=50.1457 ft$ .

Hence,

The distance from hot air balloon to the ground $AC=50.1457 ft$ .

6 0

3 years ago