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UkoKoshka [18]
3 years ago
8

Let A = {1, 2, 3, 4, 5} and B = {2, 4}. What is A ∩ B? (1 point)

Mathematics
2 answers:
Darina [25.2K]3 years ago
7 0

Answer:

{2, 4}.

Step-by-step explanation:

A ∩ B is the set of elements that are in both A and B so it is:

{2, 4}.

Rainbow [258]3 years ago
5 0

Answer:

{2, 4}

Step-by-step explanation:

Intersection is the elements that two or more sets have in common. In A and B, they share {2, 4} in common.

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Question is unclear to me ,, can you rewrite it in a nicer way so i can answer?
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2 years ago
Assume that a driver faces the following loss distribution:Outcome Probability12,000 0.15 0 0.851. What is the expected loss?2.
xxMikexx [17]

Answer:

- 1800 ; 4284.8579 ;

Step-by-step explanation:

Given the table :

Outcome _____ probability

-12000 ________ 0.15

__ 0 __________ 0.85

Expected loss, m: Σx*p(x)

(-12000 * 0.15) + (0 * 0.85)

-1800 + 0 = - 1800

Standard deviation = sqrt(Var(x))

Var(x) = Σx²*p(x) - m²

(-12000^2 * 0.15) + (0^2 * 0.85)] - 1800^2

21,600,000 - 3240000

= 18360000

Standard deviation = sqrt(18360000)

Standard deviation = 4284.8579

3 0
2 years ago
Roy’s Used Cars has 12 trucks, 20 cars and 15 SUV’s on the lot. If the Roy randomly gives away a vehicle to some lucky customer,
malfutka [58]
<h2>Answer:</h2><h2>The probability that Roy gives randomly an SUV = 15 / 47</h2>

Step-by-step explanation:

The total number of used cars owned by Roy = 47

[12 trucks + 20 cars + 15 SUV = 47 cars]

The total number in sample space, n (S) = 47

The probability that Roy is giving away and SUV = ?

Let A be the event that Roy is giving an SUV

Total no of SUV's , n (A) = 15

The probability of giving an SUV, P (A) = n (A) / n (S)

                      P (A)  = 15 / 47

                     

4 0
3 years ago
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Answer:

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3 years ago
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garik1379 [7]
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3 years ago
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