So 10.38 gal at 2.289 oer gal but you want american mony so round 2.289 to two decimal places so 2.29 per gallon
2.29 times 10.38=23.7702 but you just cross out the '2' in the ten-thousanth's place because 1/50 of a cent is really small
it is not possible to pay 9/10 of a cent so they just want you to round it up to 1 cent or10/10 cent
Answer: 5.14 cu in
Step-by-step explanation:
1/2 (π × d) + d, where d is the diameter of the semi
Perimeter = 1/2 (3.14 x 2) + 2
= 1/2 * 6.28 + 2
= 3.14 + 2
Answer:
(4.99y-1.99); rounded it would be (5y-2)
Step-by-step explanation:
Distribute 1/3 into the parentheses, since you can't subtract 15y-6 because they don't have the same variable.
The numbers 7, 11, 12, 13, 14, 18, 21, 23, 27, and 29 are written on separate cards, and the cards are placed on a table with th
SCORPION-xisa [38]
The probability of picking a card with an even number is
.
<h3>
What is probability?</h3>
- Probability is an area of mathematics that deals with numerical descriptions of how probable an event is to occur or how likely a statement is to be true.
- The probability of an event is a number between 0 and 1, where 0 denotes the event's impossibility and 1 represents certainty.
To find the probability of picking a card with an even number:
- There are 10 cards on which numbers are written 7, 11, 12, 13, 14, 18, 21, 23, 27, and 29.
- These cards are placed on a table with the numbers facing down.
- To find the probability of picking a card with an even number, first, we count all the even numbers written on the cards.
- 12, 14, and 18 out of 10 cards there are 3 even numbers written on the cards.
- So, the probability of picking a card with an even number is
.
Therefore, the probability of picking a card with an even number is
.
Know more about probability here:
brainly.com/question/24756209
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COMPLETE QUESTION:
The numbers 7, 11, 12, 13, 14, 18, 21, 23, 27, and 29 are written on separate cards, and the cards are placed on a table with the numbers facing down. The probability of picking a card with an even number is _____.