Answer:
1) 
2) ![\sqrt[3]{y^5}=y^{\frac{5}{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7By%5E5%7D%3Dy%5E%7B%5Cfrac%7B5%7D%7B3%7D)
3) ![\sqrt[5]{a^{12}}=a^{\frac{12}{5} }](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Ba%5E%7B12%7D%7D%3Da%5E%7B%5Cfrac%7B12%7D%7B5%7D%20%7D)
4) ![\sqrt[4]{z^{9}}=z^\frac{9}{4}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7Bz%5E%7B9%7D%7D%3Dz%5E%5Cfrac%7B9%7D%7B4%7D)
Step-by-step explanation:
1) 
We know that 
So,
2) ![\sqrt[3]{y^5}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7By%5E5%7D)
We know that ![\sqrt[3]{x}=x^{\frac{1}{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%7D%3Dx%5E%7B%5Cfrac%7B1%7D%7B3%7D)
So,
3) ![\sqrt[5]{a^{12}}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Ba%5E%7B12%7D%7D)
We know that ![\sqrt[5]{x}=x^{\frac{1}{5}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Bx%7D%3Dx%5E%7B%5Cfrac%7B1%7D%7B5%7D)
So,
4) ![\sqrt[4]{z^{9}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7Bz%5E%7B9%7D%7D)
We know that ![\sqrt[4]{x}=x^{\frac{1}{4}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7Bx%7D%3Dx%5E%7B%5Cfrac%7B1%7D%7B4%7D)
So,
We will let x equal is final weight.
170 2/3 + 5 2/12 - 3 1/2 = x
convert them all to common denominators:
170 8/12 + 25 5/12 - 3 6/12 = x
solve:
196 1/12 - 3 6/12 = x
Answer:
44 square feet were used to build the aquarium
Step-by-step explanation:
∵ The area of the rectangular prism = Lateral area + 2 Base area
∵ The top of the aquarium is open
∴ The area of the aquarium = Lateral area + Base area
∵ Lateral area = perimeter of base × height
∵ Its base is a rectangle
∵ The dimensions of the base are 4 feet and 2 feet
∵ Its height = 3 feet
∴ Perimeter of the base = 2(4 + 2) = 12 feet
∴ Area of the base = 4 × 2 = 8 feet²
∴ Area of aquarium = 12 × 3 + 8 = 36 + 8 = 44 feet²
Answer:
a. Vertically opposite angles
b. corresponding angles
c. Exterior angles
d. Supplementary angles
e. 40 degree
f. 40 degree
Step-by-step explanation:
