Left at 3 p.m
traveled 1 hr 30 min......now its 4:30 p.m.
stopped for 15 min....now its 4:45 p.m.
continued for 2 hrs 10 min....now its 6:55 p.m
so the train arrived at 6:55 p.m.
The solutions are C = 2 and C = -2
We can find this by solving for C.
C^2 - 4 = 0 ----> add 4 to both sides
C^2 = 4 ----> Take the square root of both sides
C = 2
However, since we used the square root function, we have to include a negative form of the answer as well as the positive one we found.
Answer:
1. Domain is [-4,4]
2. Zeros are (-2,0), (0,0), (2,0)
3. -4 
x < 0 and 2 < x 4 are neg and 0< x < 2is pos
Step-by-step explanation:
