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3 years ago

5

The actual length of the building is 72 feet. what is the scale of jackie's map?

1 answer:

Artist 52 [7]3 years ago

3 0

Answer:

1 in: 12 ft

Step-by-step explanation:

72 divided by 6 is 12

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Evaluate √196 <br>A.11<br>B.12<br>C.13<br>D.14

ANTONII [103]

Hello :)

196 = 14.14 so the answer is D

169 = 13.13

144=12.12

121=11.11

Have a nice day :)

5 0

3 years ago

Read 2 more answers

How do I solve x-y=11 2x+y=19

Margarita [4]

<span>x-y=11 2x+y=19
x=11+y
2(11+y)+y=19
22+2y+y=19
3y=-3
y=-1
x=11-1=10</span>

5 0

3 years ago

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Help please this has to be done today for me to get a 100

sukhopar [10]

Answer:

135/4

Step-by-step explanation:

That's 45 divided by 4/3, which is 45 times 3/4, which is 135/4

6 0

3 years ago

5. How long is the diagona of a 12 ft-by-16 ft rectangular garden?

kupik [55]

Answer:

The correct answer is option D, 20ft

Step-by-step explanation:

After drawing the picture below, you can just use pythagorean theorem to solve for the diagonal, or the hypotenuse in this case;

(Length)² + (Width)² = (Diagonal)²

(16)² + (12)² = (Diagonal)²

256 + 144 = (Diagonal)²

400 = (Diagonal)²

$\sqrt{400}$ = $\sqrt{Diagonal^{2} }$

<em>20 = Diagonal</em>

<em>Hope this helps!</em>

7 0

2 years ago

Read 2 more answers

Help please<3 for all questions with solutions plz

antiseptic1488 [7]

Answer:

a) $h = -\frac{7}{4}$ , b) $h = f\,\circ\,g (-5) = \frac{3}{2}$ , c) $h = g\,\circ\,f (-2) = \frac{3}{8}$

Step-by-step explanation:

We proceed to solve each exercise below:

a) $f(-2) +3\cdot g(0)$

$h = \frac{2\cdot (-2)}{3\cdot (-2)+5}+3\cdot \left(\frac{3}{0+4} \right)$

$h = \frac{-4}{-6+5} +3\cdot \left(\frac{3}{4} \right)$

$h = -4+\frac{9}{4}$

$h = \frac{-16+9}{4}$

$h = -\frac{7}{4}$

b) $h = f\,\circ \,g (-5)$

$h = f\,\circ\,g (x) = \frac{\frac{6}{x+4} }{\frac{9}{x+4}+5 }$

$h = f\,\circ\,g (x)= \frac{\frac{6}{x+4} }{\frac{9+5\cdot (x+4)}{x+4} }$

$h = f\,\circ\,g (x) = \frac{6}{29+5\cdot x}$

$h = f\,\circ\,g (-5) = \frac{6}{29+5\cdot (-5)}$

$h = f\,\circ\,g (-5) = \frac{3}{2}$

c) $h = g\,\circ\,f(-2)$

$h = g\,\circ \, f (x) = \frac{3}{\frac{2\cdot x}{3\cdot x + 5} + 4 }$

$h = g\,\circ\,f (x) = \frac{3}{\frac{2\cdot x +4\cdot (3\cdot x +5)}{3\cdot x +5 } }$

$h = g\,\circ \,f (x) = \frac{3\cdot (3\cdot x +5)}{2\cdot x +12\cdot x +20}$

$h = g\,\circ\,f(x) = \frac{9\cdot x +15}{14\cdot x +20}$

$h = g\,\circ\,f(-2) = \frac{9\cdot (-2)+15}{14\cdot (-2)+20}$

$h = g\,\circ\,f (-2) = \frac{-3}{-8}$

$h = g\,\circ\,f (-2) = \frac{3}{8}$

6 0

3 years ago