Based on the distance of the pitcher's mound from the home plate, the path of the ball, and the height the ball was hit, the distance the outfielder threw the ball is C. 183.0 ft.
<h3>How far did the outfielder throw the ball?</h3>
Based on the shape of a mound, the law of cosines can be used.
The distance the ball was thrown by the outfielder can therefore be d.
Distance is:
d² = 60.5² + 226² - (2 x 60.5 x 226 x Cos(39))
d ²= 33,484.42ft
Then find the square root:
d = √33,484.42
= 182.9874
= 183 ft
Find out more solving for distance at brainly.com/question/10739348
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Day 1 - 100
Day 2 - 50
Day 3 - 25
Day 4 - 15
Day 5 - 10
Day 6 - 5
Day 7 - 2.5
2 years late. Here is the answer for people in the future. It is D. g(x)=x-6
5*5+5=30
5*5-15=10
30/10= 3
If i understand the question correctly then the answer you are looking for is 9
