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Ann [662]
3 years ago
11

Simplify the expression. 28 + 18 ÷ 6 • (–3) 19 27 –23 –93

Mathematics
1 answer:
Flauer [41]3 years ago
5 0
18/6=3,3•(-3)=-9,28+(-9)=19

19 is your answer
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Evaluate.<br> (-4)=<br> (-7) = 0<br> Please help ASAP!!
denis-greek [22]
  • Answer:

<em>(-4)³ = (-4)(-4)(-4) = 16(-4) = - 64</em>

<em>(-7)² = (-7)(-7) = 49</em>

<em>(-)×(-) = +</em>

<em>(-)×(+) = -</em>

4 0
3 years ago
Factor Completely: 12x2 + 22x + 6 A) (2x+ 3)(6x + 2) B) 6(x + 1)(2x + 1) C) 2(2x + 3)(3x + 1) D) 2(2x + 1)(3x + 3)
tia_tia [17]

Answer:

C) 2 (2x + 3) (3x + 1)

Step-by-step explanation:

12x² + 22x + 6

2 ( 6x² + 11x + 3 )

2 [ 6x² + 9x + 2x + 3 ]

2 [ 3x ( 2x + 3 ) + 1 ( 2x + 3 ) ]

2 ( 2x + 3 ) ( 3x + 1 )  ⇒ C

7 0
3 years ago
What is the energy of a photon of orange light with a frequency of 4.84 x 1014 Hz?
cestrela7 [59]
I don’t understand your question can you go into more detail please
8 0
3 years ago
A random sample of 77 fields of corn has a mean yield of 26.226.2 bushels per acre and standard deviation of 2.322.32 bushels pe
PSYCHO15rus [73]

Answer:

Therefore the  95% confidence interval is (25,707.480 < E < 26,744.920)

Step-by-step explanation:

n = 77

mean u = 26,226.2  bushels per acre

standard deviation s = 2,322.32

let E = true mean

let A = test statistic

Find 95% Confidence Interval

so

let  A =  (u - E) *  (\sqrt{n}  / s)   be the test statistic

we want      P( average_l <  A  < average_u )  = 95%

look for  lower 2.5%  and the upper 97.5%  Because I think this is a 2-tail test

average_l =  -1.96  which corresponds to the 2.5%

average_u = 1.96

P(  -1.96  <  A  <  1.96)  =  95%

P(  -1.96  <  (u - E) *  (\sqrt{n}  / s)  <  1.96)  =  95%

Solve for the true mean E ok

E   <   u + 1.96* (s  / \sqrt{n})

from  -1.96  <  (u - E) *  (\sqrt{n}  / s)

E < 26,226.2 +  1.96*( 2,322.32 / \sqrt{77} )

E < 26,226.2 +  1.96*( 2,322.32 / \sqrt{77} )

E < 26,226.2 +  518.7197348105429466

upper bound is 26,744.9197

or

u - 1.96* (s  / \sqrt{n})  < E

26,226.2 -  518.7197348105429466  < E

25,707.48026519  < E

lower bound is 25,707.48026519

Therefore the  95% confidence interval is (25,707.480 < E < 26,744.920)

7 0
3 years ago
Estimate the sum 5.89 7 1/12​
Agata [3.3K]

Answer:

13

Step-by-step explanation:

Estimate 5.89 to 6.

5.89 ≈ 6

Estinate 7 1/12 to 7.

7.083 ≈ 7

Estimate the sum.

7 + 6 = 13

3 0
3 years ago
Read 2 more answers
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