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lozanna [386]
3 years ago
6

Find the slant height for a right circular cone with a radius of 3 and a height of 5.

Mathematics
2 answers:
babymother [125]3 years ago
5 0

Answer: l = \sqrt{34}

Step-by-step explanation:

The slant height of a cone is given by

l = \sqrt{h^{2}+r^{2}  }

h= 5

r = 3

Therefore :

l = \sqrt{5^{2}+3^{2}  }

l= \sqrt{25+9}

l = \sqrt{34}

jok3333 [9.3K]3 years ago
5 0

Answer:

The slant height is √34

Step-by-step explanation:

This problem bothers on mensuration of shapes, in particular the cone

We can solve for the slant height of a cone using Pythagoras theorem

N/B kindly see attached for your reference

Assuming all units in cm

Given data

Say that the slant height is x

Radius r= 3cm

Height h= 5cm

Applying Pythagoras theorem we have

x²=h²+r²

x=√h²+r²

Substituting our data into the expression we have

x=√5²+3²

x=√25+9

x=√34

The slant height is x=√34

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Given:

Radius of a cylinder = 5 units.

Surface area of the cylinder = 160\pi

To find:

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Solution:

Surface area of a cylinder is:

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Putting r=5, A=160\pi in the above formula, we get

160\pi =2\pi (5)(h)+2\pi (5)^2

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Subtract 50\pi from both sides.

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110\pi=10\pi h

Divide both sides by 10\pi.

\dfrac{110\pi}{10\pi}=h

11=h

Therefore, the height of the cylinder is 11 units.

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