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2 years ago

The pH of stomach acid is 2.7. Which of the following is the closest to the hydrogen concentration?

Mathematics

1 answer:

Dmitrij [34]2 years ago

3 0

Answer:

0.002M

Step-by-step explanation:

2.7= -log(H^+)

-2.7=log(H^+)

10^-2.7 M=H^+

0.0002M=H^+

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Can jack built 1/5 of a shed in the same time that kyle can build 5/8 of shed,

Helen [10]

<h3>Answer: 3/10 of a shed</h3>

=============================================================

Explanation:

Let's say the shed comes in 40 equal pieces. Each piece takes the same amount of time to assemble. Why am I picking 40? Because 8*5 = 40.

This will allow us to rewrite the fractions with a common denominator.

1/5 = 8/40 .... multiply top and bottom by 8
5/8 = 25/40 .... multiply top and bottom by 5

So Jack can build 8/40 of the shed in the same amount of time Kyle can build 25/40 of the shed.

Instead of writing fractions (which honestly are a pain to deal with), I'm going to write "8 pieces" and "25 pieces" to represent "8/40" and "25/40" respectively. Just keep in mind that there are 40 pieces total.

So again, Jack can assemble 8 pieces in the time it takes Kyle to assemble 25 pieces.

---------------

The ultimate goal is to have Kyle assemble 40 pieces while Jack puts together some unknown number of pieces (some number between 8 and 40). Let's say it's x.

We can then form this proportion

$\frac{\text{Jack's initial 8 pieces}}{\text{x pieces}}=\frac{\text{Kyle's initial 25 pieces}}{\text{goal of 40 pieces}}$

which simplifies or cleans up to

5/x = 25/40

-----------------

Let's solve for x using cross multiplication

8/x = 25/40

8*40 = x*25

320 = 25x

25x = 320

x = 320/25

x = 12.8

So in the time it takes Kyle to assemble all 40 pieces, Jack can put together 12.8 pieces of the shed. However, we can't have Jack put together some fractional piece, because each "piece" is as small as it gets. We can't get any smaller. It would be like saying a fractional part of an atom or a lego block.

So we'll round 12.8 down to 12.

Jack can assemble 12 pieces in the time it takes Kyle to assemble 40 pieces.

Let's then convert this back to fraction form

12 pieces = 12/40 of a shed = 3/10 of a shed.

8 0

2 years ago

credit cards place a three-digit security code on the back of cards.what is the probability that a code starts with the number 7

Andrew [12]

So the numbers on the credit card can start with any single-digit number

So it could start with;
0
1
2
3
4
5
6
7
8
Or 9

We are looking for the odds of it starting with a 7

There is only one 7, so the numerator is 1
There are then nine other possible numbers it could be, and counting the number 7, there is a total of ten different possibilities, so 10 is the denominator

So the odds of the card starting with a 7 is
1/10

5 0

2 years ago

Do this and thanks and tell me why you think it was a b or c maybe d

tino4ka555 [31]

<h2><u>Answer:</u></h2>

=> B) The amount of popcorn that fits in a particular container.

<h2><u>Explanation:</u></h2>

=> The amount of space that a substance or object occupies, or that is enclosed within a container is known as <u>volume.</u><u> </u> The first & third option measures the surface area while the fourth option measures the distance covered. Thus, the second option (b) is the correct answer.

$\infty \infty \infty$

6 0

2 years ago

Read 2 more answers

You start at (8, 2). You move right 1 unit and down 2 units

vekshin1

(9,0)

X=8+1=9
Y=2-2=0

Hope it helps

6 0

2 years ago

What is the period of the sinusoid given by y=-4sin( <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B2%CF%80%7D%7B3%7D%20" id="Te

Sonja [21]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\
% function transformations for trigonometric functions
\begin{array}{rllll}
% left side templates
f(x)=&{{ A}}sin({{ B}}x+{{ C}})+{{ D}}
\\\\
f(x)=&{{ A}}cos({{ B}}x+{{ C}})+{{ D}}\\\\
f(x)=&{{ A}}tan({{ B}}x+{{ C}})+{{ D}}
\end{array}
\\\\
-------------------\\\\$

$\bf \bullet \textit{ stretches or shrinks}\\
\left. \qquad \right. \textit{horizontally by amplitude } |{{ A}}|\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{ B}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the y-axis}$

$\bf \bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
$

$\bf \bullet \textit{vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{function period or frequency}\\
\left. \qquad \right. \frac{2\pi }{{{ B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\\\
\left. \qquad \right. \frac{\pi }{{{ B}}}\ for\ tan(\theta),\ cot(\theta)$

with that template in mind, let's see

$\bf \begin{array}{llll}
y=&-4sin(&\frac{2\pi }{3}x)\\
&A&B
\end{array}\qquad period\implies \cfrac{2\pi }{B}\implies \cfrac{2\pi }{\frac{2\pi }{3}}\implies \cfrac{\frac{2\pi }{1}}{\frac{2\pi }{3}}
\\\\\\
\cfrac{2\pi }{1}\cdot \cfrac{3}{2\pi }\implies 3$

8 0

2 years ago

Read 2 more answers