A cylinder has a volume of 432 cubic meters. What is the volume of a cylinder with dimensions one-third of the original?

2 answers:

alexandr1967 [171]3 years ago

5 0

Cylindervolume=hpir^2

V=432
432=hpir^2=original

if each is divided by 3 then
h turns to (1/3)h
r turns to (1/3)r
input and find the effect

(1/3)hpi[(1/3)r]^2
(1/3)hpi(1/9)r^2
move 1/9 to front
(1/27)hpir^2
compared to original volume (which was hpir^2)

so therefor we multiply the original volume by 1/27

432*1/27=16

the new volume is 16 cubic meters

Arturiano [62]3 years ago

3 0

Finally with knew knowledge i have found a more correct answer*

so in order to find out 1/3 of our dimentions
(since we size 1/3 on our height and radius)
all we have to do is divide by 27
423 ÷ 27 = 16
our correct answer is 27 cubic meters³
:P

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mafiozo [28]

Answer:

$x$ = 12

Step-by-step explanation:

The shape ABCDEF is an irregular polygon.

The sum of the interior angles of any regular or irregular polygon = (n - 2) x 180 (where n is the number of sides of the polygon).

Therefore, the sum of the interior angles of shape ABCDEF = (6 - 2) x 180 = 720°

So to find the value of $x$ , we need to add together all the interior angles and equal it to 720, then solve for $x$ .

Before we do that, we need to determine angle F.

From inspection, we can see that angle F and 52° are a linear pair. We know that a linear pair of angles add up to 180°, so F + 52 = 180 ⇒ F = 180 - 52 = 128°

Therefore:

A + B + C + D + E + F = 720

(10 $x$ - 5) + 108 + (8 $x$ - 3) + (14 $x$ - 25) + 133 + 128 = 720

Collect like terms:

10 $x$ + 8 $x$ + 14 $x$ - 5 + 108 - 3 - 25 + 133 + 128 = 720

Combine like terms:

32 $x$ + 336 = 720

Subtract 336 from both sides:

32 $x$ = 384

Divide both sides by 32:

$x$ = 12

8 0