Because this is a second degree equation you will have 2 solutions. When you take the square root of a number you have to account for both the positive and negative roots. Since the square root of 289 is 17 then your solutions are +17 and -17.
Answer:
a) 
b) It takes 5.390 years to pay off the loan.
Step-by-step explanation:
(a) The differential equation for the variation in the amount of the loan M is

We can express this equation as:

(b) We can calculate this as M(t)=0

It takes 5.390 years to pay off the loan.
Answer:
DE
Step-by-step explanation:
By Pythagoras AB^2 = 12^2 - 6^2 = 108
AB = sqrt 108 = 10.39 to nearest hundredth
The perpendicular from M to DC will be parallel and equal to AB so it = 10.39.
Also AB^2 = CB * DB
108 = 6 * DB
DB = 108/6 = 18
so DC = 18-6 = 12
MD^2 = (1/2*12)^2 + 108 = 144
so MD = 12