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Digiron [165]
4 years ago
12

Which situation can be represented by the equation. Y+19=22

Mathematics
1 answer:
marusya05 [52]4 years ago
5 0

Answer:3

Step-by-step explanation:

19 + 3=22

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lukranit [14]
The simplified form is 20x^2. Because you 2x*2, you get 4x. You multiply that by 5x, and then you get your answer.
8 0
3 years ago
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A polynominal function that describes an enclosure is v(x)=1500x_x2 where x is the length of the fence in feet what is the maxim
Maksim231197 [3]

Answer:

The answer is below

Step-by-step explanation:

A polynominal function that describes an enclosure is v(x)=1500x-x2 where x is the length of the fence in feet what is the maximum area of the enclosure

Solution:

The maximum area of the enclosure is gotten when the differential with respect to x of the enclosure function is equal to zero. That is:

V'(x) = 0

V(x) = x(1500 - x) = length * breadth.

This means the enclosure has a length of x and a width of 1500 - x

Given that:

v(x)=1500x-x². Hence:

V'(x) = 1500 -2x

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x = 1500 / 2

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The maximum area = 562500 feet²

3 0
3 years ago
Which of the functions have a range of all real numbers greater than or equal to 1 or less than or equal to -1? check all that a
kirill115 [55]
I believe it is A and D
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If L=√(x^2+y^2), dx/dt =-4, dy/dt=3, find dL/dt when x=4 and y=3
yulyashka [42]

Hello,

L=\sqrt{x^2+y^2} \\\\\dfrac{dx}{dt}=-4\\\\\dfrac{dy}{dt}=3\\\\x=4, y=3\\\\\dfrac{\partial L} {\partial x} =\dfrac{x}{\sqrt{x^2+y^2}} \\\\\dfrac{\partial L} {\partial y} =\dfrac{y}{\sqrt{x^2+y^2}} \\\\\dfrac{dL}{dt} =\dfrac{\partial L} {\partial x}*\dfrac{dx}{dt}+\dfrac{\partial L} {\partial y}*\dfrac{dy}{dt}\\\\=-4*\frac{-4}{\sqrt{4^2+3^2}} +3*\frac{3}{\sqrt{4^2+3^2}}\\\\=\dfrac{16}{5} +\dfrac{9}{5} \\\\=5\\

5 0
3 years ago
I need help plz someone
stich3 [128]

Answer:

5C 6D

Step-by-step explanation:

5, a^2 = b^2 + c^2

6,

A is wrong because two distinct lines intersect at 1 point only or 0 (they will never intersect when they are parallel)

B & C are wrong because lines contain infinite point

E is wrong because 2 parallel lines will never intersect, as the result, their common points = 0

6 0
4 years ago
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