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2 years ago

It is well-defined collection of distinct objects A.class B.elements C.Group D.Set

Mathematics

1 answer:

Elena L [17]2 years ago

4 0

Answer

hope correct

D

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2 years ago

A runner completed a 26.2-mile marathon in 210 minutes. a. Estimate the unit rate, in miles per minute. Round your answer to the

ivanzaharov [21]

Answer:

Unit rate by which the runner completed the marathon is 0.13 miles per minute.

Step-by-step explanation:

A runner competed a marathon of 26.2 miles in 210 minutes.

we can get unit rate by unitary method.

∵ In 210 minutes a runner completes the distance = 26.2 miles

∴ In 1 minute runner will complete the distance = $\frac{26.2}{210}$

= 0.125 miles per minute

≈ 0.13 miles per minute

Therefore, unit rate by which the runner completed the marathon is 0.13 miles per minute.

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2 years ago

What is the value of the digit 2 in the number 425,611?

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2 years ago

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Yahoo creates a test to classify emails as spam or not spam based on the contained words. This test accurately identifies spam (

Amiraneli [1.4K]

Answer and Step-by-step explanation:

The computation is shown below:

Let us assume that

Spam Email be S

And, test spam positive be T

Given that

P(S) = 0.3

$P(\frac{T}{S}) = 0.95$

$P(\frac{T}{S^c}) = 0.05$

Now based on the above information, the probabilities are as follows

i. P(Spam Email) is

= P(S)

= 0.3

$P(S^c) = 1 - P(S)$

= 1 - 0.3

= 0.7

ii. $P(\frac{S}{T}) = \frac{P(S\cap\ T}{P(T)}$

$= \frac{P(\frac{T}{S}) . P(S) }{P(\frac{T}{S}) . P(S) + P(\frac{T}{S^c}) . P(S^c) }$

$= \frac{0.95 \times 0.3}{0.95 \times 0.3 + 0.05 \times 0.7}$

= 0.8906

iii. $P(\frac{S}{T^c}) = \frac{P(S\cap\ T^c}{P(T^c)}$

$= \frac{P(\frac{T^c}{S}) . P(S) }{P(\frac{T^c}{S}) . P(S) + P(\frac{T^c}{S^c}) . P(S^c) }$

$= \frac{(1 - 0.95)\times 0.3}{ (1 -0.95)0.95 \times 0.3 + (1 - 0.05) \times 0.7}$

= 0.0221

We simply applied the above formulas so that the each part could come

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2 years ago