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3 years ago

When the outliers are removed, how does the mean change?

Mathematics

2 answers:

NeTakaya3 years ago

5 0

Answer:

The mean remains the same.

Step-by-step explanation:

15 and 35 are our outliers, so if you add everything you get 150, and divide it by 6 to get the mean, you get 25. now remove the outliers. you add 23, 24, 26, 27 to get 100. divide that and you get 25. thus the mean remains the same.

jok3333 [9.3K]3 years ago

3 0

<span>In statistics, an outlier is an observation point that is distant from other observations.

Given the points
15, 23, 24, 26, 27 and 35

Notice, that the points 15 and 35 are distance from the other points and hence are outliers.

The mean of the observations including the outliers is given by
$\frac{15+23+24+26+27+35}{6} = \frac{150}{6} =25$

The mean of the observations without the outliers is given by
$\frac{23+24+26+27}{4} = \frac{100}{4} =25$

Therefore, </span>when <span>the outliers are removed, the mean remains the same.</span>

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frutty [35]

Answer:

$y=\dfrac{3x}{e}+\dfrac{4}{e}$

this is the equation of the tangent at point (-1,1/e)

Step-by-step explanation:

to find the tangent line we need to find the derivative of the function g(x).

$g(x) =e^{x^3}$

we know that $\frac{d}{dx}(e^{f(x)})=e^{f(x)}f'(x)$

$g'(x) =e^{x^{3}}(3 x^{2})$

$g'(x) =3 x^{2} e^{x^{3}}$

this the equation of the slope of the curve at any point x and it also the slope of the tangent at any point x. hence, g'(x) can be denoted as 'm'

to find the slope at (-1,1/e) we'll use the x-coordinate of the point i.e. x = -1

$m =3 (-1)^{2} e^{(-1)^{3}}\\m =3e^{-1}\\m=\dfrac{3}{e}$

using the equation of line:

$(y-y_1)=m(x-x_1)$

we'll find the equation of the tangent line.

here (x1,y1) =(-1,1/e), and m = 3/e

$(y-\dfrac{1}{e})=\dfrac{3}{e}(x+1)\\y=\dfrac{3x}{e}+\dfrac{3}{e}+\dfrac{1}{e}\\$

$y=\dfrac{3x}{e}+\dfrac{4}{e}$

this is the equation of the tangent at point (-1,1/e)

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3 years ago

Write the slope-intercept form of the equation of the line that is perpendicular to AB and passes through Point X. Show all work

aleksandr82 [10.1K]

Answer:

Equation of line is y=(12/5)x+2

Step-by-step explanation:

The slope of line AB is -5/12. The line passing X is perpendicular to line AB and hence have a slope of 12/5. The slope intercept form is given by y=mx+c.

Now, point X satisfies the equation. Plugging in the slope of the line we end up with

y=(12/5)*x+c, now to find c

-10=(12/5)*(-5)+c, c=2

Equation of line is y=(12/5)x+2

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