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alex41 [277]
3 years ago
5

When the outliers are removed, how does the mean change?

Mathematics
2 answers:
NeTakaya3 years ago
5 0

Answer:

The mean remains the same.

Step-by-step explanation:

15  and 35 are our outliers, so if you add everything you get 150, and divide it by 6 to get the mean, you get 25. now remove the outliers. you add 23, 24, 26, 27 to get 100. divide that and you get 25. thus the mean remains the same.

jok3333 [9.3K]3 years ago
3 0
<span>In statistics, an outlier is an observation point that is distant from other observations.

Given the points
15, 23, 24, 26, 27 and 35

Notice, that the points 15 and 35 are distance from the other points and hence are outliers.

The mean of the observations including the outliers is given by
\frac{15+23+24+26+27+35}{6} = \frac{150}{6} =25

The mean of the observations without the outliers is given by
\frac{23+24+26+27}{4} = \frac{100}{4} =25

Therefore, </span>when <span>the outliers are removed, the mean remains the same.</span>
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if the result, when solving a system by either elimination or substitution, is -5 = -5, the solution is:​
Bond [772]

Answer:

Infinitely many solutions

Step-by-step explanation:

When the solved system has the same number on each side, the system has infinite solutions.

3 0
2 years ago
Please help asap 25 pts
nikitadnepr [17]

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4 0
3 years ago
Read 2 more answers
Jackson's front door is 42 inches wide and 84 inches tall. He got a circular table with a 96 inch diameter. Will he be able to f
chubhunter [2.5K]
NO,  

42 inches wide
<span>height = 84 </span>
Diagonal=square root of ((42*42)+(84*84))=sq root 8820=93.91
<span>She purchased a circular table that is 96 inches in diameter. </span>
as the table is more in than the diagonal,
it will not fit through the door.
<span>Answer: No</span>
8 0
3 years ago
A sphere and a cylinder have the same radius and height. The volume of the cylinder is 21m. what is the volume of the sphere.​
Goshia [24]

Answer:

The volume of the sphere is 14m³

Step-by-step explanation:

Given

Volume of the cylinder = 21m^3

Required

Volume of the sphere

Given that the volume of the cylinder is 21, the first step is to solve for the radius of the cylinder;

<em>Using the volume formula of a cylinder</em>

The formula goes thus

V = \pi r^2h

Substitute 21 for V; this gives

21 = \pi r^2h

Divide both sides by h

\frac{21}{h} = \frac{\pi r^2h}{h}

\frac{21}{h} = \pi r^2

The next step is to solve for the volume of the sphere using the following formula;

V = \frac{4}{3}\pi r^3

Divide both sides by r

\frac{V}{r} = \frac{4}{3r}\pi r^3

Expand Expression

\frac{V}{r} = \frac{4}{3}\pi r^2

Substitute \frac{21}{h} = \pi r^2

\frac{V}{r} = \frac{4}{3} * \frac{21}{h}

\frac{V}{r} = \frac{84}{3h}

\frac{V}{r} = \frac{28}{h}

Multiply both sided by r

r * \frac{V}{r} = \frac{28}{h} * r

V = \frac{28r}{h} ------ equation 1

From the question, we were given that the height of the cylinder and the sphere have equal value;

This implies that the height of the cylinder equals the diameter of the sphere. In other words

h = D , where D represents diameter of the sphere

Recall that D = 2r

So, h = D = 2r

h = 2r

Substitute 2r for h in equation 1

V = \frac{28r}{2r}

V = \frac{28}{2}

V = 14

Hence, the volume of the sphere is 14m³

4 0
3 years ago
Read 2 more answers
Suppose that the value of a stock varies each day from $13 to $24 with a uniform distribution. (a) Find the probability that the
bogdanovich [222]

Answer:

a. P= 0.6364

b. P = 0.3636

c. Q = $21.25

d. P = 0.5

Step-by-step explanation:

given data

value of a stock varies = $13 to $24

solution

P (stock value is more than $17)

P = \frac{(24-17)}{(24-13)}

P =  \frac{7}{11}

P = 0.6364

and

P (value of the stock is between $17 and $21)

P = \frac{(21-17)}{(24-13)}

P = \frac{4}{11}

P = 0.3636  

and  

Let the upper quartile be Q

\frac{(24 - Q)}{(24 - 13)} = 0.25

\frac{(24 - Q)}{11} = 0.25

(24 - Q) = 2.75

so

Q = $21.25

and

P(X > 20 | X > 16)

P = \frac{(24-20)}{(24-16)}

P = \frac{4}{8}

P = 0.5

3 0
3 years ago
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