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riadik2000 [5.3K]
3 years ago
7

Plz help ASAP!!!!!!!!!!! IT HAS TO BE CORRECT!

Mathematics
1 answer:
iren [92.7K]3 years ago
3 0

Answer:

(9,8)

Step-by-step explanation:

multiply both x and y by -1 and add 5 to the y value

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z=80°<em><u>(</u></em><em><u>corresponding</u></em><em><u> </u></em><em><u>angles)</u></em>

<em><u>x+z=180°(linear \: pair \: ) \\ 80°  + x = 180°  \\ x= 100°</u></em>

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2 years ago
Is 2x + y = 5 linear
frutty [35]
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7 0
3 years ago
Lydia spent 4/5 of her money on a mobile phone and 2/3 of the remaining amount on a bag. She had $60 left. How much more money d
KengaRu [80]
The answer is 600 because 1 out 3 is 60 so to find the bag multiply by two while to find 1 out 5 of her monet take 60 times 3 which is 180. 180 times 4 is the money she spent on her mobile phone so take the money spent on her mobile phone(720)minus the amount of money spent on the bag(120)
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Find the sum of the first<br>20 odd numbers.​
konstantin123 [22]

Answer:

Hi there.....

Step-by-step explanation:

This is ur answer......

1, 3, 5, 7, 9, 11, 13, 15.................39

Therefore the total sum = 400

hope it helps you,

mark me as the brainliest....

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7 0
3 years ago
Read 2 more answers
The family of solutions to the differential equation y ′ = −4xy3 is y = 1 √ C + 4x2 . Find the solution that satisfies the initi
slega [8]

Answer:

The correct option is 4

Step-by-step explanation:

The solution is given as

y(x)=\frac{1}{\sqrt{C+4x^2}}

Now for the initial condition the value of C is calculated as

y(x)=\frac{1}{\sqrt{C+4x^2}}\\y(-2)=\frac{1}{\sqrt{C+4(-2)^2}}\\4=\frac{1}{\sqrt{C+4(4)}}\\4=\frac{1}{\sqrt{C+16}}\\16=\frac{1}{C+16}\\C+16=\frac{1}{16}\\C=\frac{1}{16}-16

So the solution is given as

y(x)=\frac{1}{\sqrt{C+4x^2}}\\y(x)=\frac{1}{\sqrt{\frac{1}{16}-16+4x^2}}

Simplifying the equation as

y(x)=\frac{1}{\sqrt{\frac{1}{16}-16+4x^2}}\\y(x)=\frac{1}{\sqrt{\frac{1-256+64x^2}{16}}}\\y(x)=\frac{\sqrt{16}}{\sqrt{{1-256+64x^2}}}\\y(x)=\frac{4}{\sqrt{{1+64(x^2-4)}}}

So the correct option is 4

8 0
3 years ago
Read 2 more answers
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