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2 years ago

Find the unknown size please I really need answers

Mathematics

1 answer:

katen-ka-za [31]2 years ago

8 0

Answer:

z=80°(corresponding angles)

 $x+z=180°(linear \: pair \: ) \\ 80° + x = 180° \\ x= 100°$ 

y=100 ° (alternate angles)

<h2>Hope it helps you<3</h2>

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There are 88 girls and 96 boys in the sixth-grade what is the rate of girls to boys

BlackZzzverrR [31]

Answer:

It has to be A because its the only one that makes sense

Step-by-step explanation:

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3 years ago

The sum of 3 consecutive odd numbers is 183 ?

irina [24]

Answer:

The answer is 61.

Step-by-step explanation:

Let, the numbers are: x, (x+2), (x+4)

Now, x+x+2+x+4 = 183

3x + 6 = 183

3x = 177

x = 59

So, second number would be: (x+2) = (59+2) = 61

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2 years ago

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ASAP!! Please help me. I will not accept nonsense answers, but will mark as BRAINLIEST if you answer is correctly with solutions

ololo11 [35]

Answer:

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-AC I hope this helps<3

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3 years ago

Which are the solutions of x2 = 19x + 1?

Finger [1]

Answer:

$(\frac{19-\sqrt{365}} {2},\frac{19+\sqrt{365}} {2})$

Step-by-step explanation:

we have

$x^2=19x+1$

we know that

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-x^{2}-19x-1=0$

$a=1\\b=-19\\c=-1$

substitute in the formula

$x=\frac{-(-19)\pm\sqrt{-19^{2}-4(1)(-1)}} {2(1)}$

$x=\frac{19\pm\sqrt{365}} {2}$

$x=\frac{19+\sqrt{365}} {2}$

$x=\frac{19-\sqrt{365}} {2}$

$(\frac{19-\sqrt{365}} {2},\frac{19+\sqrt{365}} {2})$

therefore

StartFraction 19 minus StartRoot 365 EndRoot Over 2 EndFraction comma StartFraction 19 + StartRoot 365 EndRoot Over 2 EndFraction

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3 years ago

Read 2 more answers

(-1) + (-7) answer with work shown

lesya [120]

Answer is -8

(-1)+(-7) turns into (1)+(7)=8 and then back to original which will be -8

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3 years ago

Find the unknown size please I really need answers ​

Find the unknown size please I really need answers