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Rasek [7]
2 years ago
7

Find the unknown size please I really need answers ​

Mathematics
1 answer:
katen-ka-za [31]2 years ago
8 0

Answer:

z=80°<em><u>(</u></em><em><u>corresponding</u></em><em><u> </u></em><em><u>angles)</u></em>

<em><u>x+z=180°(linear \: pair \: ) \\ 80°  + x = 180°  \\ x= 100°</u></em>

<em><u>y=</u></em><em><u>100 </u></em><em><u>° </u></em><em><u>(</u></em><em><u>alternate</u></em><em><u> </u></em><em><u>angles</u></em><em><u>)</u></em>

<h2><em><u>Hope </u></em><em><u>it </u></em><em><u>helps</u></em><em><u> you</u></em><em><u><</u></em><em><u>3</u></em></h2>
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According to an​ airline, flights on a certain route are on time 80 ​% of the time. suppose 10 flights are randomly selected and
natulia [17]
<span>(a) This is a binomial experiment since there are only two possible results for each data point: a flight is either on time (p = 80% = 0.8) or late (q = 1 - p = 1 - 0.8 = 0.2).
​(b) Using the formula:</span><span>
P(r out of n) = (nCr)(p^r)(q^(n-r)), where n = 10 flights, r = the number of flights that arrive on time:
P(7/10) = (10C7)(0.8)^7 (0.2)^(10 - 7) = 0.2013
Therefore, there is a 0.2013 chance that exactly 7 of 10 flights will arrive on time.
​(c) Fewer than 7 flights are on time means that we must add up the probabilities for P(0/10) up to P(6/10).
Following the same formula (this can be done using a summation on a calculator, or using Excel, to make things faster):
P(0/10) + P(1/10) + ... + P(6/10) = 0.1209
This means that there is a 0.1209 chance that less than 7 flights will be on time.
​(d) The probability that at least 7 flights are on time is the exact opposite of part (c), where less than 7 flights are on time. So instead of calculating each formula from scratch, we can simply subtract the answer in part (c) from 1.
1 - 0.1209 = 0.8791.
So there is a 0.8791 chance that at least 7 flights arrive on time.
(e) For this, we must add up P(5/10) + P(6/10) + P(7/10), which gives us
0.0264 + 0.0881 + 0.2013 = 0.3158, so the probability that between 5 to 7 flights arrive on time is 0.3158.
</span>
6 0
2 years ago
In the reaction 2HgO(s) --&gt; 2Hg(l) + O2(g) we measure the evolution of gas to determine the rate of reaction. At the beginnin
djverab [1.8K]

Answer:

0.034 L/min

Step-by-step explanation:

The rate of reaction is the volume change (ΔV) divided by the time(t) and divided by the coefficient of the compound in the reaction. The coefficient of O₂ is 1, so:

R = (0.36 - 0.02)/10

R = 0.034 L/min

4 0
3 years ago
8. A substance has a half life of 2.347 minutes.
mina [271]

Answer:

a.) 4 half lives have passed

b) 9.388 minutes

Step-by-step explanation:

Formula for exponential growth / decay is given as:

A=A_0b^{\frac{t}{c}}

Where A is the final population

A_0 is the initial population

b is the growth factor

c is the time taken for the growth 'b'

t is the amount of time

Here, we are given that:

A = 6. 9 grams

A_0 = 110.4 grams

b = \dfrac{1}{2}

c = 2.347 min

To find:

a.) Number of half lives taken for the decay.

b.) Total time in the decay.

Solution:

a.) Number of half lives taken for the decay is nothing but equal to \frac{t}{c}.

Putting the values in the formula, we get:

6.9=110.4\times \frac{1}2^{\frac{t}{c}}\\\Rightarrow 6.9=110.4\times 0.5^{\frac{t}{c}}\\\Rightarrow 0.0625=0.5^{\frac{t}{c}}\\\Rightarrow \dfrac{t}{c} =4

Therefore, the answer is:

<em>4 half lives </em>have passed.

b.) Total time of decay. We have to find the value of t here.

From answer of part a.):

\dfrac{t}{c} =4\\\Rightarrow \dfrac{t}{2.347} =4\\\Rightarrow t =\bold{9.388\ min}

7 0
2 years ago
There is a direct path from Gayle's house to the store. Due to construction, the direct route is closed and Gayle must travel 6
Elina [12.6K]

Answer:

<em><u>c2=10</u></em>

Step-by-step explanation:

8^2+6^2=c2

64+36=120

c2=square root of 120..which is 10

3 0
3 years ago
Mrs. Nicholas baked two batches of cookies. The first batch consisted of 120 gingerbread cookies and the second batch consisted
shusha [124]

Answer:

i think 2/15 of the cookies

Step-by-step explanation:

hope this helps

3 0
1 year ago
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