All categories

3 years ago

WILL MARK BRAINLIST TO WHO EVER ANSWERS WILL FULL STEPS!! I WILL BRAINLIST!!

Mathematics

2 answers:

alexgriva [62]3 years ago

4 0

P = (5,-2)

R = (-5,1)

Q= (4,-5)

Step-by-step explanation:

First of all, find the line of symmetry, so the opposite side of the original shape. Next, if one of the corners (for example R) is one square away from the line of symmetry, you will have to put the corner on square away from the line on the other side. You must repeat this, join the dots, and you are done. Hope it helps

Genrish500 [490]3 years ago

4 0

answer:

A. B. AND C. BUT WHAT ARE YOU REFERING TO? C? B? A? YOUR QUESTION IS NOT VERY CLEAR LUV SORRY.

step-by-step explanation:

payback :) <3

You might be interested in

Suzannes school are painting a rectangular mural outside the buillding that will be 15 feet by 45 feet the students are also goi

tatuchka [14]

Answer:

THE LENGTH OF THE STUDENTS PAINTING=15/3=5

THE BREADTH OF THE STUDENTS PAINTING=45/3=15

AREA OF THEIR PAINTING=15×5=75

4 0

3 years ago

Someone please help :) will mark brainliest :)

Nitella [24]

Answer:

a+b

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Please solve all 3 I need this quick

AnnyKZ [126]

Answer: i have absolutely no idea

Step-by-step explanation:

5 0

3 years ago

At what point on the paraboloid y = x2 + z2 is the tangent plane parallel to the plane 3x + 2y + 7z = 2? (if an answer does not

Nikitich [7]

If $f(x, y, z) = c$ represent a family of surfaces for different values of the constant $c$ . The gradient of the function $f$ defined as $\nabla f$ is a vector normal to the surface $f(x, y, z) = c$ .

Given the paraboloid

$y = x^2 + z^2$ .

We can rewrite it as a scalar value function f as follows:

$f(x,y,z)=x^2-y+z^2=0$

The normal to the paraboloid at any point is given by:

$\nabla f= i\frac{\partial}{\partial x}(x^2-y+z^2) - j\frac{\partial}{\partial y}(x^2-y+z^2) + k\frac{\partial}{\partial z}(x^2-y+z^2) \\ \\ =2xi-j+2zk$

Also, the normal to the given plane $3x + 2y + 7z = 2$ is given by:

$3i+2j+7k$

Equating the two normal vectors, we have:

$2x=3\Rightarrow x= \frac{3}{2} \\ \\ -1=2 \\ \\ 2z=7\Rightarrow z= \frac{7}{2}$

Since, -1 = 2 is not possible, therefore there exist no such point on the paraboloid $y = x^2 + z^2$ such that the tangent plane is parallel to the plane 3x + 2y + 7z = 2.

4 0

3 years ago

5 1/4 + 2 3/4 = what is the summ

Burka [1]

5 + 2 = 7
1/4 + 3/4 = 1
7 + 1 = 8
Your answer is 8

7 0

3 years ago

Read 2 more answers