Solve for y. 6 x + 2y = z
2 answers:
Answer:
Step-by-step explanation:
Isolate the variable, y. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.
PEMDAS =
Parenthesis
Exponents & roots
Multiplication
Division
Addition
Subtraction
& is the order of operation.
First, subtract 6x from both sides:
6x (-6x) + 2y = z (-6x)
2y = z - 6x
Next, divide 2 from both sides:
(2y)/2 = (z - 6x)/2
y = (z - 6x)/2
y = (z/2) - 3x
is your answer.
~
You might be interested in
It's going to be kind of crazy, but you need to use Pythagorean's Theorem for this. That will look like this: 
. FOIL out the left side to get 
. FOIL out the first of the 2 expressions on the right to get 
, and the second of the 2 to get 4x. Our equation now looks like this: 
. Combine like terms to get an equation that still has square roots in it that we have to deal with: 
and 
. We will square both sides to get rid of the square root sign. 
. This is a polynomial now that can be factored to solve for x. Bring the 2x over by subtraction and set the polynomial equal to 0. 
. Factor out an x, leaving us with x(x-2)=0. That means that x = 0 or x - 2 = 0 and x = 2. Of course if we are solving for the length of a side we know it can't have a side length of 0, so it must have a side length that is a multiple of 2. x = 2