100cm2 that is the answer I got
See the picture attached to better understand the problem
we know that
If two secant segments are drawn to a <span>circle </span><span>from an exterior point, then the product of the measures of one secant segment and its external secant segment is equal to the product of the measures of the other secant segment and its external secant segment.
</span>so
jl*jk=jn*jm------> jn=jl*jk/jm
we have
<span>jk=8,lk=4 and jm=6
</span>jl=8+4----> 12
jn=jl*jk/jm-----> jn=12*8/6----> jn=16
the answer isjn=16
Answer:
16
Step-by-step explanation:
The distance is given by
d = sqrt( (x2-x1) ^2 + ( y2-y1) ^2)
Since the x values are the same
d = sqrt( ( y2-y1) ^2)
d = sqrt( (( -6 - 10)^2))
d = sqrt((-16) ^2)
d = 16
We can also just find the number of squares between the points since the x value is the same.
10 - -6
10+6
16