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3 years ago

Please.solve the system of equations

Mathematics

1 answer:

Talja [164]3 years ago

4 0

Solve for the first variable in one of the equations, then substitute the result into the other equation.

Point Form: (3,2)

Equation form:

x = 3

y = 2

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Can someone help me with these 5 question I have attached?

Contact [7]

Example 2: x=10

Example 3: x=-1

Example 4: x=35

Example 5: a-b+c=9

Example 6: x=1, x=1/2

Further explanation:

Example 2:

$\sqrt{4x-4} =6$

Taking Square on both sides

$(\sqrt{4x-4})^2 =(6)^2\\4x-4=36\\4x=36+4\\4x=40\\\frac{4x}{4}=\frac{40}{4}\\x=10$

Example 3:

$9+\sqrt{4x+8}=11$

Subtracting 9 from both sides

$9-9+\sqrt{4x+8}=11-9\\\sqrt{4x+8}=2\\$

Taking Square on both sides

$(\sqrt{4x+8})^2=(2)^2\\4x+8=4\\4x=4-8\\4x=-4\\\frac{4x}{4}=-\frac{4}{4}\\x=-1$

Example 4:

$8+\sqrt{x+1}=2$

subtracting 8 from both sides

$8-8+\sqrt{x+1}=2-8\\\sqrt{x+1}=-6$

Taking Square on both sides

$(\sqrt{x+1})^2=(-6)^2\\x+1=36\\$

Subtracting 1 from both sides

$x+1-1=36-1\\x=35$

Example 5:

$\sqrt{a-b+c}=3$

Taking Square on both sides

$(\sqrt{a-b+c})^2=(3)^2\\a-b+c=9\\$

Example 6:

$2\sqrt{2x-1}=4x-2$

Taking square on both sides

$(2\sqrt{2x-1})^2=(4x-2)^2\\4(2x-1)=16x^2+4-16x\\8x-4=16x^2-16x+4\\8x=16x^2-16x+4+4\\8x=16x^2-16x+8\\16x^2-16x-8x+8=0\\16x^2-24x+8=0$

dividng whole equation by 8

$2x^2-3x+1=0\\2x^2-2x-x+1=\\2x(x-1)-1(x-1)=0\\(2x-1)(x-1)=0\\2x-1=0 => x=\frac{1}{2}\\x-1=0 => x=1$

Keywords: Radical Expressions, Examples

Learn more about radical expressions at:

#LearnwithBrainly

3 0

3 years ago

I dont know please help

Margaret [11]

Answer:

Step-by-step explanation:

4 0

4 years ago

Read 2 more answers

It has a coefficient of m=-1 and passes through the point (9,4) Write as an equation for rsm

OLga [1]

Answer:

y=-x+13

Step-by-step explanation:

6 0

2 years ago

Write the equation in slope intercept form (solved for y), when possible. Through (4,-3)

Kay [80]

Answer: y=-3/4x

Step by step explanation:

y-y_0=m(x-x_0)

y+3=-3/4(x-4)

y=-3/4x+3-3

y=-3/4x

m=rise/run

m=-3/4

4 0

3 years ago

The ground temperature at Brigham Airport is 17 °C. The temperature decreases by 4.9 °C for every increase of 1 kilometer above

SSSSS [86.1K]

Answer:

should be -7.5

Step-by-step explanation:

4.9×5=24.5

17-24.5=-7.5

8 0

3 years ago