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dezoksy [38]
3 years ago
14

Line Segment BC has endpoints B (3,5) and C (7,15). Find the missing coordinates of A (x,9) and D (17,y) such that AB and CD are

perpendicular to BC.
Mathematics
1 answer:
o-na [289]3 years ago
4 0

Answer:

<em>x=-7</em>

<em>y=11</em>

Step-by-step explanation:

<u>Perpendicular Vectors</u>

Two vectors defined as their endpoints \vec u= and \vec v= are perpendicular if their dot product a.b is zero. The dot product is

\vec u.\vec v=ac+bd

In other words

ac+bd=0

Let's treat all the points as the extremes of vectors, so we can easily find the missing coordinates

B (3,5) and C (7,15) define a segment, the vector  

\overrightarrow{BC}==

The point A is A (x,9), we need to form a vector with B

\overrightarrow{AB}==

this vector must be perpendicular to BC, so, applying the dot product we have

4(x-3)+40=0

4x-12=-40

x=-7

The point D is D(17,y), we need to form a vector with C

\overrightarrow{CD}==

this vector must be perpendicular to BC, so, applying the dot product we have

(4)(10)+(10)(y-15)=0

40+10y-150=0

10y=110

y=11

The points are

\boxed{A(-7,9), D(17,11)}

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3 years ago
Evaluate the dot product of (7, 5) and (- 5, 4)
melamori03 [73]

Answer:

The dot product of (7,5) and (-5,4) is -15

Step-by-step explanation:

Given

(7,5) and (-5,4)

Required

Determine the dot product

Dot product is calculated using the following formula;

a.b = {a_1b_1+a_2b_2+...+a_nb_n}

Let a = (7,5) and b = (-5,4);

The above formula becomes

a.b = {7*-5+5*4}

a.b = {-35+20}

a.b = {-15}

Hence, the dot product of (7,5) and (-5,4) is -15

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Step-by-step explanation:

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