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alekssr [168]
3 years ago
15

Find the value of C that completes the square

Mathematics
1 answer:
MatroZZZ [7]3 years ago
6 0

Answer:

Step-by-step explanation:

y^2-22y+c

complete the square ax^2+bx+c is our old formula quadratic equation

we know that to find c we will divide b/2 and square it

22/2=11

c^2=121

we have y^2-22y+121

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Answer:

Mean

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3 years ago
(x+y+2)(y+1) &lt;--- Please help,will mark brainly
kifflom [539]

Answer:

y^2+xy+x+3y+2

Step-by-step explanation:

first of all we have to multiplies the y in the second bracket for all numbers in the first bracket.

so we have:

xy+y^2+2y

now we have to do the same with 1

x+y+2

now we have to unite the two solutions

xy+y^2+2y+x+y+2

at least we have to added up the similar terms (that have the same literal part)

y^2+xy+x+3y+2

6 0
3 years ago
Noah saw some worms in his garden. He measured the length of each worm.
sergeinik [125]

Answer:

9 worms are longer than 3 inches

Step-by-step explanation:

you can just count how many are in in the rows after 3 and that is your answer

5 0
3 years ago
Identify the k-value that makes the relationship shown in the table below proportional.​
uysha [10]

Answer:

The value of k that makes the relationship shown in the table below proportional is \mathbf{\frac{1}{2}}

Step-by-step explanation:

The relation is proportional if y=kx \:or\:k=\frac{y}{x}

Putting values of x and y to find k.

For x =2 and y =1 k is: k=\frac{y}{x}=\frac{1}{2}

For x =4 and y =2 k is: k=\frac{y}{x}=\frac{2}{4} =\frac{1}{2}

For x =6 and y = 3 k is: k=\frac{y}{x}=\frac{3}{6} =\frac{1}{2}

For x = 8 and y = 4 k is: k=\frac{y}{x}=\frac{4}{8} =\frac{1}{2}

For x =10 and y = 5 k is: k=\frac{y}{x}=\frac{5}{10} =\frac{1}{2}

So, The value of k that makes the relationship shown in the table below proportional is \mathbf{\frac{1}{2}}

5 0
3 years ago
What is the length of segment AE?
nexus9112 [7]

Answer:

AE=\frac{50}{3}\ units

Step-by-step explanation:

step 1

In the right triangle ABC

Applying the Pythagoras Theorem fin the hypotenuse AC

AC^{2} =AB^{2}+BC^{2}

substitute

AC^{2} =6^{2}+8^{2}

AC^{2} =100

AC =10\ units

step 2

we know that

If two figures are similar, then the ratio of its corresponding sides is equal

so

\frac{AB}{CD}=\frac{AC}{CE}

substitute and solve for CE

\frac{6}{4}=\frac{10}{CE}\\ \\CE=4*10/6\\ \\CE=\frac{20}{3}\ units

step 3

Find the length of segment AE

AE=AC+CE

substitute the values

AE=10\ units+\frac{20}{3}\ units=\frac{50}{3}\ units

6 0
3 years ago
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