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jekas [21]
3 years ago
13

A sequence is defined by

Mathematics
2 answers:
garik1379 [7]3 years ago
5 0
I believe the answer is D.

3^2 is 9 and 4^2 is 16, and because 9/16 was the third term in the sequence, you raise both the numerator and the denominator by the number of the term minus 1.

So to find the seventh term, you raise the numerator and denominator by 7 - 1 = 6.

So the answer is 729/4096
uranmaximum [27]3 years ago
3 0
Since each term is -3/4 times the previous term we know that this is a geometric sequence with a common ratio of -3/4.  Any geometric sequence can be expressed as:

a(n)=ar^(n-1), a=initial term, r=common ratio, n=term number

Since we do know the common ratio is -3/4 and that a(3)=9/16 we can find the value of a, the initial term.

9/16=a(-3/4)^2

9/16=9a/16

1=a, so the initial term is 1 so now we have the formula for our geometric sequence.

a(n)=1*(-3/4)^(n-1)

a(n)=(-3/4)^(n-1)  so the 7th term is:

a(7)=(-3/4)^6

a(7)=729/4096
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∠1 and ∠2 are complementary. If m∠1 = 4m∠2, find m∠1
77julia77 [94]

Answer:

∠1 = 72°

Step-by-step explanation:

Complementary angles sum to 90°, thus

∠1 + ∠2 = 90, substitute ∠1 = 4∠2 , thus

4∠2 + ∠2 = 90

5∠2 = 90 ( divide both sides by 5 )

∠2 = 18°

Hence ∠1 = 90 - 18 = 72°

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3 years ago
Rewrite 50 - 15 using the distributive property and a common factor
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It is not too difficult. Just do this
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4 0
4 years ago
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Answer: What do I solve for?

Step-by-step explanation:

Do I need to solve for the slope, equation, x-int, etc?

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Find the radius of a circle with a area of 212 squared
natulia [17]

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3 0
3 years ago
In a survey of 1000 large corporations, 260 said that, given a choice between a job candidate who smokes and an equally qualifie
Usimov [2.4K]

Answer:

The 95% confidence interval for the proportion of corporations preferring a nonsmoking candidate is (0.2328, 0.2872)

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 1000, p = \frac{260}{1000} = 0.26

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.26 - 1.96\sqrt{\frac{0.26*0.74}{1000}} = 0.2328

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.26 + 1.96\sqrt{\frac{0.26*0.74}{1000}} = 0.2872

The 95% confidence interval for the proportion of corporations preferring a nonsmoking candidate is (0.2328, 0.2872)

4 0
3 years ago
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