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jekas [21]
3 years ago
13

A sequence is defined by

Mathematics
2 answers:
garik1379 [7]3 years ago
5 0
I believe the answer is D.

3^2 is 9 and 4^2 is 16, and because 9/16 was the third term in the sequence, you raise both the numerator and the denominator by the number of the term minus 1.

So to find the seventh term, you raise the numerator and denominator by 7 - 1 = 6.

So the answer is 729/4096
uranmaximum [27]3 years ago
3 0
Since each term is -3/4 times the previous term we know that this is a geometric sequence with a common ratio of -3/4.  Any geometric sequence can be expressed as:

a(n)=ar^(n-1), a=initial term, r=common ratio, n=term number

Since we do know the common ratio is -3/4 and that a(3)=9/16 we can find the value of a, the initial term.

9/16=a(-3/4)^2

9/16=9a/16

1=a, so the initial term is 1 so now we have the formula for our geometric sequence.

a(n)=1*(-3/4)^(n-1)

a(n)=(-3/4)^(n-1)  so the 7th term is:

a(7)=(-3/4)^6

a(7)=729/4096
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The difference of two numbers is 16 the greater number is five less than four times a small number find the two numbers
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Step-by-step explanation:

1. Set up the equations

   Let x = the greater number

  and y = the smaller number. Then

(1) x - y = 16

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You have a system of two equations:

\begin{cases}(1) & x - y = 16\\(2) & x = 4y - 5\end{cases}

2. Solve the equations

\begin{array}{lrcll}(3) & 4y - 5 - y & = & 16 &\text{Substituted (2) into (1)}\\& 3y - 5 & = & 16 &\text{Simplified}\\ & 3y & = & 21 &\text{Added 5 to each side}\\(4) &y & = & \mathbf{7} &\text{Divided each side by 3} \\& x - 7 & = & 16 & \text{Substituted (4) into (1)}\\& x& = & \mathbf{23} & \text{Added 7 to each side}\\\end{array}

The larger number is 23; the smaller number is 7.

3. Check

\begin{array}{rclcrcl}23 - 7& = & 16 & \qquad &23&=&4(7) - 5\\16 & = & 16 & \qquad &23& = &28 - 5\\&&& \qquad &23& = &23\\\end{array}

OK.

3 0
3 years ago
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