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miv72 [106K]
3 years ago
12

Can someone show me how to do this problem:

Mathematics
1 answer:
avanturin [10]3 years ago
3 0

Answer:

\{x \in R | x \neq 3\}

\{x \in R | x < 3 \cup x > 3\}

\{x | x > 3, x \in R\} \cup\{x | x < 3, x \in R\}

Step-by-step explanation:

To find the domain of a rational expression like \frac{14x}{x-3} you need to find out where the denominator is 0 because you cannot divide by 0

So, take the denominator x - 3 and set it to zero and solve for x

x - 3 = 0

x = 3

So the domain is all real numbers but where x = 3. You can write this in a few different ways in set notation.

---------------------------------------

NOTE

R = real numbers

\in = element of

| = such that

---------------------------------------

\{x \in R | x \neq 3\}

<u>Or you could write it this way</u>

\{x \in R | x < 3 \cup x > 3\}

<u>Or you could write it this way</u>

\{x | x > 3, x \in R\} \cup\{x | x < 3, x \in R\}


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