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3 years ago

find the value of r so that the line passes through (-5,4) and (3,r) so that the slope is equal to -1/2.

Mathematics

1 answer:

amm18123 years ago

5 0

Answer:

ZERO

Step-by-step explanation:

All steps in the picture , I hope this is a clearly.

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Use your trendline to find the temperature of your Spaghettios after 40 minutes. Is this an example of interpolation or extrapol

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Answer:

in 40 minutes, 15 degrees Farenheit will be e

Step-by-step explanation:

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3 years ago

Drugs that reduce emotionality make big money for drug companies. These drugs undergo extensive testing, some of which is done w

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3 years ago

The quotient 250/5/8 tells about how far a sloth may move in one hour. How far can a sloth go in 90 minutes?

VladimirAG [237]

$Answer: \text{Sloth covers }9\frac{3}{8}\text{in 90 minutes.}$

Explanation :

Since we have given that

$\text{in 1 hour sloth may move = }\frac{250}{5\times 8}$

$\text{ In 60 minutes , sloth may move = }\frac{25}{4}$

$\text{ In 1 minute, it may move = }\frac{25}{4\times 60}\\\\\text{ In 1 minute, it may move = }\frac{5}{48}$

$\text{ In 90 minutes, it may move}\\=\frac{5\times 90}{48}\\ \\=\frac{75}{8}\\\\=9\frac{3}{8}$

∴ $\text{Sloth covers }9\frac{3}{8}\text{in 90 minutes.}$

8 0

3 years ago

Please answer this correctly without making mistakes

zheka24 [161]

Both are correct

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4 0

3 years ago

Read 2 more answers

In order to estimate the average time spent on the computer terminals per student at a local university, data were collected for

Setler [38]

Answer:

7) d)

standard error of the mean of one sample of 'n' observation = 0.20

8) a)

The margin of Error = 0.392

9) d

The 95% of confidence intervals are (8.61 , 9.39)

Step-by-step explanation:

solution:-

The Given data sample size 'n' = 81

Given Population standard deviation 'σ' = 1.8 hours

The standard error of the mean of one sample of 'n' observation is

Standard error (SE)

= $\frac{S.D}{\sqrt{n} }$

= σ / √n

= $\frac{1.8}{\sqrt{81} } =0.2$

standard error of the mean of one sample of 'n' observation = 0.20

Solution:-

The Given data sample size 'n' = 81

Given Population standard deviation 'σ' = 1.8 hours

Given the probability is 0.95

The z- score = 1.96 at 0.05 level of significance.

The margin of Error = $\frac{z_{0.95} S.D}{\sqrt{n} }$

= $\frac{1.96 (S.D)}{\sqrt{n} }$

= $\frac{1.96 (1.8)}{\sqrt{81} }$

= 0.392

The margin of Error = 0.392

Solution:-

The 95% of confidence intervals are

$(x^{-} - 1.96\frac{S.D}{\sqrt{n} } , x^{-} + 1.96\frac{S.D}{\sqrt{n} } )$

$(9 - 1.96\frac{1.8}{\sqrt{81} } , 9+ 1.96\frac{1.8}{\sqrt{81} } )$

(9 - 0.392 , (9 + 0.392)

(8.609 , 9.392)

The 95% of confidence intervals are (8.61 , 9.39)

4 0

3 years ago