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3 years ago

6

A square has an area of 64 square inches. What is the length of one side of the square? What is the length of the diagonal

1 answer:

Mkey [24]3 years ago

4 0

Answer:

8 and 11.3137

Step-by-step explanation:

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I would appreciate this a lot if someone could help me with this.

VARVARA [1.3K]

Answer: 1 - 2 = u got this

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

John’s father is 5 times older than John and John is twice as old as his sister Alice. In two years time, the sum of their ages

oksano4ka [1.4K]

Answer:

John’s age is 8 years

Step-by-step explanation:

Let

x -----> John’s father's age

y -----> John’s age

z -----> John’s sister's age

we know that

$x=5y$ -----> equation A

$y=2z$

$z=y/2$ -----> equation B

$(x+2)+(y+2)+(z+2)=58$

$x+y+z+6=58$

$x+y+z=52$ -----> equation C

Substitute equation A and equation B in equation C and solve for y

$5y+y+y/2=52$

Multiply by 2 both sides to remove the fraction

$10y+2y+y=104$

$13y=104$

$y=8$

<em>Find the value of x</em>

$x=5(8)=40$

<em>Find the value of z</em>

$z=8/2=4$

therefore

John’s father's age is 40 years

John’s age is 8 years

John’s sister's age is 4 years

7 0

3 years ago

You have a wire that is 20 cm long. You wish to cut it into two pieces. One piece will be bent into the shape of a square. The o

Aleksandr [31]

Answer:

Therefore the circumference of the circle is $=\frac{20\pi}{4+\pi}$

Step-by-step explanation:

Let the side of the square be s

and the radius of the circle be r

The perimeter of the square is = 4s

The circumference of the circle is =2πr

Given that the length of the wire is 20 cm.

According to the problem,

4s + 2πr =20

⇒2s+πr =10

$\Rightarrow s=\frac{10-\pi r}{2}$

The area of the circle is = πr²

The area of the square is = s²

A represent the total area of the square and circle.

A=πr²+s²

Putting the value of s

$A=\pi r^2+ (\frac{10-\pi r}{2})^2$

$\Rightarrow A= \pi r^2+(\frac{10}{2})^2-2.\frac{10}{2}.\frac{\pi r}{2}+ (\frac{\pi r}{2})^2$

$\Rightarrow A=\pi r^2 +25-5 \pi r +\frac{\pi^2r^2}{4}$

$\Rightarrow A=\pi r^2\frac{4+\pi}{4} -5\pi r +25$

For maximum or minimum $\frac{dA}{dr}=0$

Differentiating with respect to r

$\frac{dA}{dr}= \frac{2\pi r(4+\pi)}{4} -5\pi$

Again differentiating with respect to r

$\frac{d^2A}{dr^2}=\frac{2\pi (4+\pi)}{4}$ > 0

For maximum or minimum

$\frac{dA}{dr}=0$

$\Rightarrow \frac{2\pi r(4+\pi)}{4} -5\pi=0$

$\Rightarrow r = \frac{10\pi }{\pi(4+\pi)}$

$\Rightarrow r=\frac{10}{4+\pi}$

$\frac{d^2A}{dr^2}|_{ r=\frac{10}{4+\pi}}=\frac{2\pi (4+\pi)}{4}>0$

Therefore at $r=\frac{10}{4+\pi}$ , A is minimum.

Therefore the circumference of the circle is

$=2 \pi \frac{10}{4+\pi}$

$=\frac{20\pi}{4+\pi}$

4 0

2 years ago

What is the Pythagorean theorem and how do I use it?

Leviafan [203]

I actually just learned this in 8th grade and it was so easy its crazy but its honestly simple it helps you solve the triangles and things and the equation is a squared + b squared = c squared and the a and b you would plug in the sides of the triangle or whatever shape your working with and square those numbers then find c by adding the two and then you square the c at the end and that will be your answer.

4 0

3 years ago

Read 2 more answers

Answer to this please!

lapo4ka [179]

according to mid point theorem:

Bf=1/2CE

=45

3 0

3 years ago