Question

Which of the following are possible values of r?rac%7B3%7D%7B16%7D%20" id="TexFormula1" title=" {r}^{2 } = \frac{3}{16} " alt=" {r}^{2 } = \frac{3}{16} " align="absmiddle" class="latex-formula">
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Answer 1

Answer:

$r=\frac{\sqrt{3} }{4}$    and    $r=-\frac{\sqrt{3} }{4}$

Step-by-step explanation:

when you solve for r in the given equation, you need to apply the square root property, which gives positive and negative answers (both should therefore be considered):

$r^2=\frac{3}{16} \\r=+/-\sqrt{\frac{3}{16}} \\r=+/-\frac{\sqrt{3} }{4}$

then you need to include these two possible solutions:

$r=\frac{\sqrt{3} }{4}$    and    $r=-\frac{\sqrt{3} }{4}$