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iVinArrow [24]
3 years ago
10

-6n5x^3÷18nx^712m^8y^6÷-9my^4​

Mathematics
1 answer:
umka2103 [35]3 years ago
5 0

Answer:

(-n^4 - 4 m^7 x^4 y^2)/(3 x^4)

Step-by-step explanation:

Simplify the following:

(-6 n^5 x^3)/(18 n x^7) + (12 m^8 y^6)/(-9 m y^4)

The gcd of -6 and 18 is 6, so (-6 n^5 x^3)/(18 n x^7) = ((6 (-1)) n^5 x^3)/((6×3) n x^7) = 6/6×(-n^5 x^3)/(3 n x^7) = (-n^5 x^3)/(3 n x^7):

(-1 n^5 x^3)/(3 n x^7) + (12 m^8 y^6)/(-9 m y^4)

Combine powers. (-n^5 x^3)/(3 n x^7) = (n^(5 - 1) x^(3 - 7) (-1))/3:

-(n^(5 - 1) x^(3 - 7))/3 + (12 m^8 y^6)/(-9 m y^4)

5 - 1 = 4:

-(n^4 x^(3 - 7))/3 + (12 m^8 y^6)/(-9 m y^4)

3 - 7 = -4:

-(n^4 x^(-4))/3 + (12 m^8 y^6)/(-9 m y^4)

The gcd of 12 and -9 is 3, so (12 m^8 y^6)/(-9 m y^4) = ((3×4) m^8 y^6)/((3 (-3)) m y^4) = 3/3×(4 m^8 y^6)/(-3 m y^4) = (4 m^8 y^6)/(-3 m y^4):

(4 m^8 y^6)/(-3 m y^4) - (n^4)/(3 x^4)

Combine powers. (4 m^8 y^6)/(-3 m y^4) = (4 m^(8 - 1) y^(6 - 4))/(3 (-1)):

-(n^4)/(3 x^4) + (4 m^(8 - 1) y^(6 - 4))/(-3)

8 - 1 = 7:

-(n^4)/(3 x^4) + (4 m^7 y^(6 - 4))/(-3)

6 - 4 = 2:

-(n^4)/(3 x^4) + (4 m^7 y^2)/(-3)

Multiply numerator and denominator of (4 m^7 y^2)/(-3) by -1:

-4/3 m^7 y^2 - (n^4)/(3 x^4)

Put each term in -(n^4)/(x^4×3) - (4 m^7 y^2)/3 over the common denominator 3 x^4: -(n^4)/(x^4×3) - (4 m^7 y^2)/3 = (-n^4)/(3 x^4) - (4 m^7 x^4 y^2)/(3 x^4):

-n^4/(3 x^4) - (4 m^7 x^4 y^2)/(3 x^4)

-n^4/(3 x^4) - (4 m^7 x^4 y^2)/(3 x^4) = (-n^4 - 4 m^7 x^4 y^2)/(3 x^4):

Answer: (-n^4 - 4 m^7 x^4 y^2)/(3 x^4)

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Answer: 6.36lb

Step-by-step explanation:

Step-by-step explanation:

Total Weight of the package = weight of product + weight of box

Weight of empty box =0.88lb

Total weight of the box is =7.24lb

Let Weight of product inside box=w

Let wet of empty box =y

Total weight = F

Then,

F=y+w

Since F=7.24lb. y=0.88

Then, w=F-y

w=7.24-0.88

w=6.36lb

The weight of the product is 6.36lb

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2 years ago
I’m having trouble with this plz help.
RoseWind [281]

Answer:

The answer is 56. Here's why:

Step-by-step explanation:

Pythagorean Therom works for any right triangle, and it states (a)²+(b)²=(c)². A and B are the height and base, and C is the hyptoanuse. We don't know the height, but we know the rest of the information:

(a)²+(33)²=(65)². This simplifies to (a)²+1089=4225. If we subtract 1089 from each side, we get (a)²=3136. The √3136 (Sqaure root of 3136) is 56.

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Step-by-step explanation:

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What expression can be used to find the nth term in the sequence 5,7,9, 11,...?
Vesna [10]

Answer:

The required expression which can be used to find the nth term in the sequence is:

a_n=2n+3

Hence, the fourth option i.e. 2n+3 is the correct option.

Step-by-step explanation:

Given the sequence

5, 7, 9, 11,...

An arithmetic sequence has a constant difference 'd' and is defined by  

a_n=a_1+\left(n-1\right)d

computing the differences of all the adjacent terms

7-5=2,\:\quad \:9-7=2,\:\quad \:11-9=2

The difference between all the adjacent terms is the same and equal to

d = 2

So

  • a₁ = 5
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Thus, the nth term of the sequence is

a_n=a_1+\left(n-1\right)d

substitute a₁ = 5 and d = 2 in the sequence

a_n=2\left(n-1\right)+5

a_n=2n+3

Therefore, the required expression which can be used to find the nth term in the sequence is:

a_n=2n+3

Hence, the fourth option i.e. 2n+3 is the correct option.

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