It takes 40 minutes more going up or 40/60 = 0.67 hours
more.
Let us say that:
t = the time required for him running down
t + 0.67 = time required for him running up
Since the distance of running up and down must be equal
therefore:
(3 miles / hr) * (t + 0.67) = (5 miles / h) * t
3 t + 2.01 = 5 t
2 t = 2.01
t = 1.005 hr
So the total length of the hike is:
length = 2 * (5 miles / hr) * (1.005 hr)
<span>length = 10.05 miles</span>
The factors are just numbers that can be multiplied to receive the number that is given.
The factors of 24 are: 1, 2, 3, 4, 6, 8, 12, 24.
1 × 24 = 24
2 × 12 = 24
3 × 8 = 24
4 × 6 = 24
Answer:
Step-by-step explanation:
2005 AMC 8 Problems/Problem 20
Problem
Alice and Bob play a game involving a circle whose circumference is divided by 12 equally-spaced points. The points are numbered clockwise, from 1 to 12. Both start on point 12. Alice moves clockwise and Bob, counterclockwise. In a turn of the game, Alice moves 5 points clockwise and Bob moves 9 points counterclockwise. The game ends when they stop on the same point. How many turns will this take?
$\textbf{(A)}\ 6\qquad\textbf{(B)}\ 8\qquad\textbf{(C)}\ 12\qquad\textbf{(D)}\ 14\qquad\textbf{(E)}\ 24$
Solution
Alice moves $5k$ steps and Bob moves $9k$ steps, where $k$ is the turn they are on. Alice and Bob coincide when the number of steps they move collectively, $14k$, is a multiple of $12$. Since this number must be a multiple of $12$, as stated in the previous sentence, $14$ has a factor $2$, $k$ must have a factor of $6$. The smallest number of turns that is a multiple of $6$ is $\boxed{\textbf{(A)}\ 6}$.
See Also
2005 AMC 8 (Problems • Answer Key • Resources)
Preceded by
Problem 19 Followed by
Problem 21
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All AJHSME/AMC 8 Problems and Solutions
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.
1×10+7×1+6×0.1+0×0.01+1×0.001 is the answer
Answer:
5.8
Step-by-step explanation:
tangent = opposite over adjacent
10*tan(30) ≈ 5.774
round to the nearest 10th
5.8