If it reaches its maximum height a t=3 its velocity must be zero at t=3
dy/dx=0 at t=3
dA/dx=4x+12=24 at t=3 so this does not apply
dB/dx=-4x+12=0 at t=3 and B=13 at t=3 so B applies
dC/dx=-4x-12=-24 at t=3 so this does not apply
dD/dx=-4x-12=-24 at t=3 so this does not apply
dE/dx=-4x-12=-24 at t=3 so this does not apply
So only quadratic B: reaches a maximum height of 13 feet at 3 seconds.
Let the number be x.
9(1/4)+x=x/3+6
Simplify.
2.25+x=x/3+6
-6 -6
-3.75+x=x/3
•3 •3
-11.25+3x=x
-3x -3x
-11.26=-2x
5.625=x
please make me brainliest ;)
Answer:
(x+5)(x-3)
Step-by-step explanation:
We can factor the equation to be
(x+5)(x-3)